midterm1

midterm1 - Name Student PID BICD100 Midterm version A key 1...

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Name_________________________________ Student PID __________________ 1 BICD100 Midterm 1/24/05 version A key 1.) In nature, fruits of the plant Plectritis congesta can be wingless or winged (see below) – both types are quite common. To try to understand the genetic control of this trait, you collect 3 winged fruits and 2 wingless fruits, grow plants from them, and do some controlled crosses with these plants. The results are as follows: CROSS: PROGENY FRUIT: ________ # WINGED # WINGLESS winged #1 selfed 91 0 winged #2 selfed 90 32 wingless #1 selfed 0 85 wingless #2 selfed 0 92 winged #1 x wingless #1 161 0 winged #2 x wingless #2 29 31 winged #2 x winged #3 44 0 a. How many genes appear to be involved in determining whether fruits are winged or wingless? One b. Which is the dominant trait, winged or wingless (2 pts)? Winged c. Given the results in the table, what phenotypic classes do you expect to find among the selfed progeny of winged #3, and in what proportions (4 pts)? Results of cross winged #2 x winged #3 tell you that winged #3 must be homozygous for the dominant allele, therefore expect all winged. 2.). On your first day as a volunteer in the neonatal unit of a hospital, you make the unfortunate mistake of getting 3 babies mixed up so you don’t know which is which. All 3 babies look much the same to you, so you can’t tell from the babies features which baby belongs to which couple. Not wanting to confess your blunder, and having blood typing kits at your disposal, you decide to try to figure out whose baby is whose on your own. You determine that baby #1 has blood type A, #2 has blood type O, and #3 has blood type AB. From medical records, you find out that the blood types of the 3 sets of parents are as follows: Jensens: mother is type AB, father is type O #1 McDonalds: mother is type A, father is type O #2 Andersons: mother is type A, father is type B #3 a. For each baby whose parents can be determined with certainty from this information, indicate above whose baby is whose (9 pts). (See above) b. Based on your answers in part a, what blood types could future children of the McDonalds possibly have, and what is the probability of each type (4 pts)? Mother’s genotype must be I A i and father’s is ii. So 1/2 of children expected to be blood type A (genotype I A i) and other half type O (genoptype ii).
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midterm1 - Name Student PID BICD100 Midterm version A key 1...

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