HW7_solutions - NS Fmsr SOLVED _ b) V319 ummbafifl rs WM-...

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Unformatted text preview: NS Fmsr SOLVED _ b) V319 ummbafifl rs WM- CM!) 515 ~susm-rm 2) a3 = -9.8mns2 ‘3 S) Us'éo :- 'Umog '1' r.) v / /1 0'3» a v0 SIYLOL = O ‘ Slm‘l E W Wax) sung = o n) va = v9 -o.%:§zk 309 20 2' f IQ) Axb=vpt no.3_n_n ’b D '2 32 SOLUTIOd =0 who“. '-' ma)!— V‘éo ‘4‘3 £33 - Pow 50 = v 2’0 on) svd—‘LQtt— % fim % @ ‘3? b “" ’ (a? mud—hp 5 WW. :0) 8 = UDSIdOL‘t:'3 9'31t2‘ C9 also ‘L 6; gay {0) 0: v0 S‘n'd‘bz “i 9.9) ‘tz Q Btu... gnome . r . TD 1}»0 WM»— @ ' d :AXBlo 7— 'AXD 7 WM 2. 3 Ax‘slp;& a: = vowsott: (vat: M 9 : 'UOJoL)tUt1)A w.»me Oaks ‘1 %AS MISSufi SOMQIW-Kj a S @ U0 GOSOL szo N0“ ash“ ,1 ‘s ‘ ‘ ? Lek flagrnd: 2'1) 9: ’UOGJSd 2'27.) sh a) b) (v) 02) Z O 5 ‘ I , @ .2) =333t‘l:l 7g {3312‘ ; 2- 913’ G) g=Utt—‘L9t‘ ' Z. w 32” a w; .8! 94?] ' 7— ‘ g @ o: Ultl“q'9tz ’5 J52:0) 9565 .\V j ‘ z : _ :7 :‘0592‘ ; @ > d:3m 301,va main? '7/ HFTEK RKCOMS‘IOMTIOM 5! RfiFLELHOU .. I'D ngmg¢mz sou/(70:01 533‘s TIM. bad] :‘s Wham») Thrown mm a 121:1- Vclocd‘v! abhor : +19 m dcdc (hot is m Mk8 dsremm-WWVSWdWWv! Smut, 119. ML TS mouuij at V00 11? h‘¢ (“a/Lt— 3 Vgoa'UDO—E +7213; CO 3.8: a”: + C—‘I-kigz): ® W» v3; Don't, + (qr—9.91403 @ w vow magma <9 as $311M boo!- deck 17%; up; @ ‘59 — —-o.?>mls7' 7: (9 TM. VD=CUD—o%mls27i)f CD gHwaw THM WHEN U = = . 33 O 43 38mm v -931 t = 0 y‘amsams HIM/v» . 3: v’t “mt? b = m f kwow '1’an may ‘43: AXE“)- d. Mflmflfl “A I?! - 9955,}: OF- 1V... —5 __\ l ‘5 A U510 : (1190» + (1) 4.21193) — (1)90 - 0.3?ztzh {1 W V‘Lcfi ‘32, 2.5“: Y/ S _ 0.393 i 7, + (1252—3184 (1%)); s7- 7' W VD“ tt «i 1259 an. (9.17/- 891: .. 8 a“ [H] XLS9L+OIZ¢SZ = IQ.C.Zg\ s ‘l 12.3"? (QM/HM N ma“; /‘ "a? < a P510415... Of-L 21l.191 . 6: - W / e47!”- 0186 Han-Cat um' ‘ a) Flam rt muck. 509% h Wmm— 50° Us LSM 4:: 7 0 Se :0“ ‘ —-—-—9X 91095 can: Cawvwarzsur A k .A Va; [5 ‘ULlocuhr, of be” \133 VBF —- loo hub: ._.s _~. 3) v5 ,+ vm (5+0 a wad Mtwfla‘e —--'Ucm g ‘5 hem WM’M phage rf -\ ....\ g b) VB 1“: ’ch‘ {S H, In AS Sumo“ U POSSlblc Sfismm ' Séiflczrcw («gm/.2 gEQmS Fog‘ConL. I) 1)“ = - L? casso" ’5) 1/930 .-. -- 1.2 ml; Sm$o° a Z a 7- O 6 z. —-<).8’mlsz ) {x ) ac‘a' ’néd’) *3) So we}, we)"> 1) 50 ya = —x.emls9‘- 9.3mm at E =Vaxo ‘gc— ' 1. ‘7’ j [ Ar gauge” 3&3) ' Va 2 (—1.<Xc.9550°): - (1.8 +9.8t); ~—c 0°” + s 1 0“ g19) VB“ vs“ C as! 1.. v» D 4 ) ESOLUTIafl Hoe.) flow Tm. dam. Ims 3591-? (a: Mao nus w mu, Veda) 8) —1.s= ~LY§smsoDi= 4; (9.951) {'2 M920 t" +1-281A500 t — LS = o 3 ' 7- 1 \ 2 [— H.9OSP LgSHCS-Uo “Ins-3 1} t F“ WM!“ L3798 ; Cow’s ‘tz 0:13) 1?!“ 1’177‘4/ "W H ( 417‘ Pact}; o¢__1___2/____ ' W Vgls = (-13 CoSSOO + 113;” a;st A» “ (mam 300% ‘ VW——————-’ . .xi +93“: +vm514lcf)é '1)“g -_ ‘Ucls A with} O= -\.8’us50°+v&&eoslo° Us“; 1.115? \/ 0335 a; t=a=e3 , 'Fm am) yew ..> I. f f _ Va“3 = (r 1.st +128“ 0.985).;- (5.591 +12%? 0.1134, )1 W" 11- <1 '7) 3a ‘7‘ an; ‘ (-I-IS’H 0‘ 2: M, + (5597 +123“ DARE) We. LJCuvT‘ lvc‘g‘ = MN; To BN‘R Mamhfinum a Him? .‘ ._ ‘- u 9" ECU - O - /Z{( MS’H osaguguflo ‘3 s Seit’ I 0: «1.13% + 0.9é9‘8’vw + 0.31:? + 0.0.1505ngIf 0’ (1.1%9‘1-‘0-‘mfl = 1.0 1236, i, Va” 7- 0.1615 mLS haw—L mam “m. aJkoc‘S Solm-bw)w$tg a W‘ .dfikrcM’ awroadm) O(\ m nudg— Page F%ea.1_ofi lZ// \— SOLUTION First (ietermine the velocity VC of the (393E at the point Where the 0021] impacts 0n the belt. Horizantai motion: (15(3)); : [(VC )I L = «i .8 205503 x -I .1579 HE’S z ' 2 Vertical motion: (117)“: VC )vl} —2g(y — 343) zofiwfimf~QX9&X45) a 31.3311112552 (1%)” x: -5.59’7-’¥ H155 m 5 3 3.533332%. 3 4.33279, {3 = 78.32% w1 .3570 v3. :2 (12C + (VC 2 32.669 IRE/$2 vfjm 5.7156 mfg, vcm 531156 mfs :7 ’38326 03‘ vC: (4.1571) mfsfi +{-S.5974 mish’ Velocity of the bait: v3 = v3(—cosi0°i + 531103;) Reiative velocity: VGB : v6 - V3 2 v6 + (— v8) (0) v.38 is verticai. (355.3 )x 2 {I (96.3)}: _11.57%) — 1:5(—80519G)= 0, V3: L175 mis VB=1.175 11335 3;.10'3 ‘ (1?) v6.3 is minimum. Sketch the vac:th addition as shown. wQ$§t . ,2 W 2 ‘2 r G V "35a: — "B + PC - 2v3vccosss.32 a Set the derivative with respect to BB equai :0 zero. 2V3 — 23/}: cos 88.3? = 0 v3: VCCOSSS.32° = 0.16376 11155 V3 : 0.E676 .m’s 31. 10° ‘ 5 FIND mnx‘mwm spam QLOMG mum.er Putnam ofi Tmacu MON TN“— 3‘143? _. 6" . ~ L / at A 4— /’/ is I EEOI’NS E A _ {J "‘ a ‘ 6)c + - 8‘1 V L F at an We, (.50.er 2-- 3“: 3; 4 3(9‘2m \ gsm 87’ Sat—Vi *2. v < 25(2)(9 is) 7) < 27.1? S . a; /“.A/:t/r/ 7V] Gtuen lé-Soom A] A may"--- w \ I. Llme K; “g g" m“ \ /’ 300 520 Kan/kn; 9 1:: M L S n1” Tué. tNSTnN‘F‘ Suoww . = —2 v8 3 2. FIND a) .03! 5) 581A CoarLD A at __ an an“ llrfchquf‘ 5‘,an FA = 00 O m. an ‘ ‘15“; €47“ "\ .3 .— UZ —. "‘ \ a3 = “3937. 8% + -—-g en flaw-€17 S 3 Steam ‘3 ,r/L» 3'? 3 VB = HMO z- 3600 n 5 VB = SaOXIOOOE .1 [‘4‘4.”‘ 8% 3900 ‘53 3 Souvflufl —"’ _ To mwwz v8 - v“ m mew, musflm -——- __ expressed a ‘ an m‘ m Same CoorJ x’V/Vf I"? Page. to 04 IL ._.———>'A A; a A t“: L Enfi 1‘ @FL )3!)5 1.2 _, 3 67 t8 e}c :. 3.30% — c.2536”; 3"“: ,3 an : —S‘A300C.38300 V‘ _ a 3 v: O 6n :_&Sgoobflsuigooé +3 (3 vg—vn : Hum (5.30“: «080°? “11971: ._L— -ag-afi :[(‘Z 1:1 )(suiéff 105303;)4' 52 -' (0‘1! "V3 ‘52- ) Q. ~ ‘ o A m W o@ %—H77.ng M” t - z 3 may ( — c.9530"; 3.530921% 7.00“ q<7 Wgflm 103.659 87/ (fif/TV/“MV/TVR n v0 = {2015?}; E'Fwo Q Realms of (larva.an 09 TL; quk a) ‘4' p‘ ,_,. .L l \ b) “’3“ ‘2‘”); » . .wb . :2) £05 ‘ ECooLo 3*! 811m 3 ea Sham. “Zir‘rwfi-MV ( +35:Lwo§) éEgnLc ‘ 3 0" 3 29 “ ASSWMSM m x“ = L - a. + a' dr ‘3‘ ‘ EL‘é onl- ‘rwyajfiécg . A o -.—> 2-___ 1L) , m t-n a : we +1) 3 3 't E5 n .4 —> .a .— LJM €%=_\/_ Md. QHISJ—hfie": v“ 3. towards Cede/qu WM To rind EJC ) we. head? Proceepflnj Rm _5 = O I - 32.7. E4— 9 5?! Wm Uxa: 1:10 may W 213 z. (20¢st O z (90% r:- 3 _ s A A A V5 90 Q L + (103.9£*~32.1-t)3 5 .s SoLUT’ld-d A _, A RT A t=o V=éo¥m HOB-9&3! ) 3‘ 5 U=110£+ S was 4° [’1 T i | 99.312013 l2. 30 47-_'z = 12. lal “U air ’E‘so .3 .. . = -‘ ._ —* 3mg ° °“. a at (O A. 32.2})( 0*- +0.08304\ W Wmsf be, exp/mega? 2L ‘Wmm CDa rdmd-r. sulleNU "D = ~3a.2c.:s300 = ~21.%‘Zé H 6 2. __,, 2. la I = (02+ («337231) A Z . 2. [El - ‘U?’ =- (33.2)L- (27.98%) ; 16.11 “NI/v £1 2 “ml Sax“. U‘ I???“ J 5’ 5 Now) NM ,3 V :1 ’U (cosgoa: +Smxgoog) v)‘ = UM 2v 6.93300 1205.30" a 126.9550” =a> 2); 69.2244- 5 Tm ngstzo" = gouw a»); m¥e€oom mo h; a- A — 2 ‘ a,c : 0953091, + mafia Hum 121 — 12": 32.19%} 2. 2 ‘ J ’ - v ‘0 1‘ “'- 2 \‘ I“ 0 7.17.9“ -— ) a at 32. 851$ '20 (g, g: = (09-1321" = r12 \3 77M i ...
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This note was uploaded on 09/26/2008 for the course ME 215 taught by Professor Mcinerny during the Fall '08 term at University of Alabama at Birmingham.

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HW7_solutions - NS Fmsr SOLVED _ b) V319 ummbafifl rs WM-...

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