Practice Final B solutions

Practice Final B solutions - I. Three charges are...

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Unformatted text preview: I. Three charges are pasitianed as indicated in the figure. What are the horizontal and vertical components cf the act farce exerted on the +13 at? charge by the ether twu charges? harizomaf tar-rim! F ’ d:- 1 ‘- 95 N 429 N B) J L TEN 3mm '07"? @ 429w —3|2N : Jar?” J/ D} -9514 —95N 5‘! Izaw 312M Page I A proton moves in a constant electric field E from point A to point B. The magnitude of the electric field is 4.2 * It)“ NEE; and it is directed as shown in the drawing, the direction opposite to the motion of the proton. [f the distance from point A to point B is ii. I B In. what is the change in the proton's electric potential energy. EPEA — EPEB? "is EPEA @ as W flat-W Proton “Main {PK‘C A) +2.4* [III—‘5] ' my“) M 4143:. s»- {r—c Leno-'51 mm -. {guano-'51 ’5 {pr rob-Just"; '- ‘E‘fz - 4 no —2.4* Ill—'5} w s} 43* 10"51 Farms . "F 1 t (fitsrw't’wuw 75ft} - L1 wit—“.7 flparallci plate capacitor has plates ofarca 2J1] hr1 and plate separation Ill "‘ Ill—4 n1. I dielectric with F41} fills the 1trolurne between the plates. l.‘r'i’hat is the electric field at the ' midpoint between the plates if a charge of magnitude l of is deposited on each plate?I @14le ‘Wm E __ VA F air a _ .1. - ___..-— __. __ a} 2.3m wm Ca mg ‘1' a” 3/ C} 1.? too5 Wm "H 1)} hereto1 Wm y; 1/ c ': (if E] l.lxll]5Wn1 4" : [lel'g'lug Wig) Lass. firm-W and a till—W light bulb are designed for use with the same voltage. What is the ratio of die resistance of the fill-W bulb to die resistance of” the rill—W bulb? A} 1.5 t as? _ i Pr V /a. be C] 2.3 EC -— '. j; ' E 2:234 R t th- ' Eff : h} : “ESP-flag fl“; b I-——- I Page 2 Xi: he figure shows a simple RC circuit censisting of a teen-v battery in series with a Hit}— pF capacitor and a resistor. Initially, the switch 3 is open and the capaciter is uncharged. Twc seconds after the switch is closed. the veltage acress the resistor is 3'! V. s a ._ riqu IUD-DE :i—1IJIJIJF ,_ rh ch much charge is en the capaciter at that time‘.’ at t.t*1fl'3C a F a arm/2 We .__r_<°3~ C} atria—1c 63 a“: “ea D}5.2*Ifl4t’_‘ I / @6.3*104C . A particle with a mass cffiJE-rl * 10—17r kg and a charge ef +3.20 * iii—"ir C is accelerated from rest through a petential difference of 2.45 * ll]fi V. The particle then enters a uniform 1.60- T magnetic field. if the particle's veleeity is perpendicular te the magnetic field at all times. what is the magnitude cf the magnetic feree exerted on the particle“? A} zerc newtens B a)1.14*1er'“1~1 F : 51”. W i _ C) assuer'fln r; "h :3! 5' D} 4119* IU'" N UM -. @sra ID'HN A I' L- V _. Fn. L ‘T ‘P _' .‘. Ina-"Ha. '7 2 fly] _ B {4.2” U- _ Ci, M 3! _ yfl'fl .— 1; L13 ___ — .- .- LI I rfdrla I_ _ r 33‘ _ 2, E'Hrfire I .h '3 35? it! : (jester!) {We} m“ Page 3 Us: the following to answer question 1'. Two long. straight wires separated by {1.10 n: cart-)3,r currents of I B A and ti A in the same dircction as shown. “A, "a: t. Bald 6w? l isa as He; M 0F fl.1|]m--+ mij _ ,u'a I.~, flL-E IE ._. i’ff( “3 f :5: 'i. _ J. .- '—"" i . r,- E'Ir re 317 0'” 9"“ L_.#————3‘ 3W - c {Momma the magnitude of the magnetic field at the point P. ‘-——._ fl.-. -- " A} 2.4 * 10—5 T g 4.8 * 111-5 T Ct 12 t 10-5 T D} 9.6 * iii—5 T E} Zerotesia 8, A long solenoid has rt=lflflfl toms per motor. A Conducting loop ofaroa A = dill-t} in2 is placed at tho cantor of tho solcnoid with its axis paralch to that oftho solenoid as shown. MM f3") Dotcn'ninc the mutual inductance of the two coils. A} Lion-42 l" {Ail ' I B} Mania m -. “Ml-r1 #15 C} Purim _' D WHEAT @tlm1 . -1?) - o _ LI»? we. (loom) (ll) - 6. or” Page 4 Use the following to answer question 9. The figure shows a unifon‘n. 3.fl-T magnetie field that is normal to the plane of'a eondueting. eireular loop with a resistance of [.5 fl and a radius of 11(124 m. The magnetie field is direeted out of the paper as shown. Note: The area of the non—circular portion of the wire is considered negligible compared to that of' the circular loop. mat is the average eurrent around the loop ifthe magnitude of the magnetic field is doubled in 0.12s“? A} 5.6 * ltl‘r"3 A, eioekwise a} 911* 10-3 A.e1oekwise LI} 9J1” It} 3 A? eountereloekwise .E" [El—2A,,eioekwise 6'59 now? {My E} 1.3 * it] 2 A, eoantereloekwise ll Page 5 Use the fnliewing to answer question It]. A single conducting Ice-p 1with an area of 2.fl m2 rotates in a unifenn magnetic field an that the induced emf has a sinusoidal time dependence as shown. hf Mitt 7a ,asv -1|'.5 V ‘35 " flame 7-5: L-J ' 3-7 r' -. . - -. , Ar r v , -me_ 7” g ' .- “t3 2 Z. a CERT; flflctcnninc the sh'ength cf the magnetic field in which the lnepihnrm.————""”' ninsT B 2.4 T fgfisaT 315T eitasT ‘i i. Twe cnils share a ccrnrncn axis as shown in the figure. The mutual inductance cf this pair efceiis is t’ifl th. if the current in ceil l is changing at the rate nf 3.5 Ms, what is the magnitude cfthe emf generated in cnil 2‘? fl (lam —' § (Qt; ecill chili ...._ —- .. _._ Ant At niss*1n4v a}IJ*tn3v , ctls*m4v P“ éfifi _ lAé flint D}L5*m4v At @li‘lflz‘t’ fl fl eleetremagnetie wave has an electrie field 1with peak value ZSDJI} NEE. What is the average energy delivered to a surface with area 211E! m3 by this wave in one minute? _ g A} 81]] T .- -:-.~_I_J£-."t-'<'E_-'fr-fld ’1}? .3 ,h 5-: Cu. 7 C. Eng 2 M s in w e. m as M i M? D} 49813} /P“‘l" 99960.1 strata-C :( ggg)éj(ae3 “MM M394. We em.- EMA/r: "W: The”??? flay of green light travels thruttgh air and is refracted as It enters a glass prism shown in the figure. An unknewn liquid is in contact with the right side at" the prism. The light then follows the path shrlwn. Which one at the thllewing statements ee-neerning this situation is 'L B The index efrefraetien ef the glass is smaller than that of air. he index of refi'aetien of the unknem liquid is the same as that of the glass. )1 The speed ef' light is larger in the liquid than in the glass. E} The refractive index of the liquid is the same as that of air. Page i ..- M converging lens with s fneel length of £2 em produces a 3—ern high virtual image of ti I—em high ebjeet. Which entry in the table helew is eerreet‘.’ . f image distance luetrlfmt tifffltflge woof-(eh; A} efimm?‘ M E em same side {if lens as “inject M a a 4 i: B} s ‘t ‘11 fl r b' T “‘9'; k" em :3 esiesi en ens reme- e‘. ' T— ‘ pp .1 L' MD M M I... a h g 4- r’ :- l2 em eppesite side uf lens from object " J i D! 24 em nppnsite side el' lens from object , ,l' at e r-* L 24 em same side ef'iens as ehjeet 4— |. _ :1 t“ '- _ '__ Use the fellewing to answer questien l5. If ‘ - #2 e' .. . L _ _ '- 55' L ' T.‘ 1:: The figure shows the interference pattern obtained in e tlnuhle—slit experiment using light of wavelength sen em. I L. 41:: Cantrubngntfringe ‘ ‘ij L ' ‘5 JG 7 ‘ EL — 5| i; 7 ['51 l I' I ILL-dim? 1 _._._________H I .d ‘ H - '.1- ' x x 'L I '9 I "- /l§. Wliteh ltlnge results Frern s phdst dim-tenet et 43L 4‘ W { ii mr r/ A} A r,- B]: B #7; .— Cl C Ll"? m 2' @D . e} E {I he raj/L Pagefl c— elk—'7' “’1 ‘ --/tvi~~--/ ,ffr- '-‘ ' re”? l . Light offiflflfl nm is incident upon a single slit. The resulting diffi‘aetion pattern is observed on a screen that is (1.513 In fiom the slit. The distance between the first and third minima of the diffraction pattern is [1.80 mm. Which range of 1rabies listed beiow contains the width of gin mm to {1.4 mm .r B} ll4 mm to (1.8 111111 , {3 .r AIL“ CI - ': ‘21 — (Ave; [18 mm to 1.2 mm D} |.2mmtol.firnm 5:" 1" E} I.fimmto2.flmm F L 3r I .r- 9» 4;: W amigo?) a I I C d H 4f A bomb is designed to explode .{lfl s after it is armed. The bomb is launehed from earth and aeeeierated to an unknown final speed. After reaching its final speed, however, the 4f. bomb is observed by people on earth to explode 4.25 s after it is armed. What is the final ,1} ': gr? 3‘ "4‘ at speed of the bombjust before it explodes? W , -' , '4 F 4.1;“ A} {1.995s H‘— B} [1.97m [7} 0.9396 1 a 2 I 2 x a. DEW Q. E T 2- 'A-1 if 1- U— /Ct T :: tr: 1' ‘l E} (1382:: |. "‘ e .1 P hag/en .| .- 3. H51: “4’: ._ Jfifhiehgonezoi‘ gleam—‘ng elemonigonwfigadafitiins mnesm I to an atomie exeited state? U. a: C 1s Es 2M5 fl a J {aritqu B} 132 232 211$ 35] x; Tisha-#1) REE—F; C} 153252 2pfi351 ,_... D} 151253 zpl :— Wig} E} 153253 3—---“ I f? Page 9 sample are allowed to pass through a narrow slit and may.r be considered a beam. The beam is passed between two plates that eatt'},r opposite electrical charge. The expefimenta] region eontains no magnetic fields. It is observed that the beam is defieeteel toward the negativelyr /Radiation or{and) partieles emerge(s} from a radioaetive sample. These products from the liar d] -. , . . c ge pate I mgatwe' j W M _._,_,_._r'"” [If-e, I * I. l maifiw - Whieh one of the following statements is the best eonelusion for this situation? A] The beam is onlyetrays. k _ a. g! B} The beam is only.r fl rays. C The beam is on] re s. . i' H t __ 5;. g g The beam eould be either 0'. rays or [3' rays. I, F.) The beam could be 0. rays, [5" rays, or "r rays. + - i9 a 7“ 2t]. Complete the following nuelear reaetion: 1;N + ‘rH “3- 'n + T. i“ g I A} 160 if; B} 15H C} “C o) "*N E} 2H 2t. Determine most elosely. the aetiitit],r of fiDD-[l atoms of Kit—22G, whieb has a half—life of 4D Qiflflflq J 3 6mm <5! —. NA: @Uoolé‘} C} 4:) Eq . no see Eq “ELL ‘1‘ 3" E} 1st: Bq Page 10 MEI.- The ratie ef' the abundance efearhen—l 4 te earhenel 2 in a sample efdead weed is ene r quarter the ratie fer Living, weed. If the half—life efearhen-H is 5130 years, whieh ene ef the fellewing expressiens determines henr many years age the weed died? ersrse I __Lfil =4*51ee 6-“: flat rh>~fi+fgot C} e.r5*sr3e NP Na 13} e.se*sr3e 4 .5 I F “I E) e.2s*srse lim- eJa 4’ #4.?“ .: mam t E: :. J'I'Lttlefl ; 27:“- Use the fellewing te answer questien 23. Censider the fellewing nuelear decay: :fitl 4 33,111 + .t' 23. Determine the amount et‘energ}.r released in this decay. Use the fellewhtg atemie masses: :3: Leas-seas see u; l“:jfrh = asaess e54 u; :He = 4.002 aes u; ,',n = Lees 565 u; and :p =1_eer2r’t u Ceeuersien faeters: I u = EELS MeV; l e33: Let]? " 113"“! A) asrltrtr Blee’tte-Wr ?2;,_Da;5§az ‘23E.Qf‘gflf‘f-Y.UU'TE:91: m meme-131 @rgetflflj A“? 0.00H't'i'flfm :_ tf+3'_{?qplpv E} 23* 1e '11 ?~??rre'13f 24. Which ef the fellewing hest explains why the REE ef'l Mel.»r alpha particles is math-greater; than that err-rays et‘the same energy? A Alpha particles are charged. lpha particles depesit their energy in a mueh smaller volume eftissue. l Gamma rays have smaller wavelength. D} Gamma rays have greater mementum El Alpha particles have awe frequency [W a law ‘1) 0! M dw- Page 1 I 25. Detennine the atomic number Z and the nufllean number A in the mllowing reaction: IgNafiHejHflME- A: 23+] -=: '3. *fi” 2' A I 2% A} 12 23 2. E+L-—‘? If'1-*7 3) 12 24 Jr :| D} 11 23 E} 11 22 Page 12 ...
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Practice Final B solutions - I. Three charges are...

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