HW2 Hints
2.62.
m/s
;
m/s
8
12
=
+
v
i
j
j
6
4
=
+
a
i
2
;
;
56.3
v
θ
=
D
33.7
a
θ
=
D
2.64.
Please refer to example 3 on your lecture 2 notes
.
Notice that
particle A is on the projectile,
also it is in the horizontal slotted arm. Therefore, A and the slotted arm have the
same
speed in
vertical direction
(dy/dt = 3 in./sec).
6
3
=
+
v
i
j
j
in.
/s
in/s
magnitude
6.7
v
⇒
=
3
0
=
+
a
i
in/s
2
in/s
magnitude a
3
⇒
=
2
2.81.
y
(2)
(1)
x
Key: First look at point (1) which is apex of the trajectory. So you can create two equations to
solve to unknown: u and t
1
x-direction:
1
0
0
1
x
x
x
v t
=
+
, you already know
1
8000
x
=
[1]
y-direction: use
equation. At the same time you know
v
1
y
v
1
0
y
=
at apex of the trajectory.

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