HW2_hints

HW2_hints - HW2 Hints 2.62. v = 8i + 12 j m/s; a = 6i + 4 j...

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HW2 Hints 2.62. m/s ; m/s 81 2 =+ vi j j 64 ai 2 ; ; 56.3 v θ = D 33.7 a = D 2.64. Please refer to example 3 on your lecture 2 notes . Notice that particle A is on the projectile, also it is in the horizontal slotted arm. Therefore, A and the slotted arm have the same speed in vertical direction (dy/dt = 3 in./sec). 63 vij j in. /s in/s magnitude 6.7 v ⇒= 30 in/s 2 in/s magnitude a 3 2 2.81. y (2) (1) x Key: First look at point (1) which is apex of the trajectory. So you can create two equations to solve to unknown: u and t 1 x-direction: 100 1 x x xv t , you already know 1 8000 x = [1] y-direction: use equation. At the same time you know v 1 y v 1 0 y = at apex of the trajectory.
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This note was uploaded on 09/27/2008 for the course ME 212 taught by Professor Staff during the Spring '05 term at Cal Poly.

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HW2_hints - HW2 Hints 2.62. v = 8i + 12 j m/s; a = 6i + 4 j...

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