HW2 Hints 2.62. m/s; m/s812=+vijj64=+ai2; ; 56.3vθ=D33.7aθ=D2.64. Please refer to example 3 on your lecture 2 notes. Notice thatparticle A is on the projectile, also it is in the horizontal slotted arm. Therefore, A and the slotted arm have the same speed in vertical direction(dy/dt = 3 in./sec). 63=+vijjin./s in/smagnitude 6.7v⇒=30=+aiin/s2in/smagnitude a3⇒=22.81. y (2) (1) x Key: First look at point (1) which is apex of the trajectory. So you can create two equations to solve to unknown: u and t1x-direction: 1001xxxv t=+, you already know 18000x= y-direction: use equation. At the same time you know v1yv10y=at apex of the trajectory.
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