Chemistry HW - B. 2 O, 4 C, 20 H 2Li3N(s) = 6Li(s) + N2(g)...

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Chemistry HW #3 3.3 – Ans. B. 3.6 – 4*CH4=4C+16H, 2H2O=4H +2O Ans. 2 O, 4 C, 20 H 3.12 – (a) Li3N = Li+N2, Ans. 2Li3N(s) = 6Li(s) + N2(g) (b) La2O3 + H2O = La(OH)3, Ans. La2O3 + 3H2O = 2La(OH)3 (c) NH4NO3 = N2 + O2 +H2O, Ans. 2NH4NO3 = 2N2 + O2 + 4H2O 3.40 – (a) C19H28O2 = 0.000042 mol 0.000042*(6.02*10^23)*19=4.804*10^20 Ans. 4.80*10^20 atoms of Carbon (b) 0.000042*6.022*10^23=2.53*10^19 Ans. 2.53*10^19 molecules (c) x moles*6.02*10^23*28 H=7.08*10^20, x=0.000042, Ans. 0.000042 Moles (d) 0.000042 mol*total mass of 1 mol C19H28)2, 228+28+32=288, 288*0.000042=0.012096, Ans. 0.012096 grams 3.5 (a) 75.69/12.01=6.3, 8.80/1.008=8.73, 15.51/15.999=0.969, 6.3/0.969=6.4, 8.80/0.969=8.73, 0.969/0.969=1, 12.01+1.008+15.999=29.017, 206/29=7.1 Ans. Empirical – C6H9O, Molecular – C42H63O7 (b)58.55/12.01=4.8751,13.81/1.008=13.7,27.4/14=1.957,4.8751/2.4,13.7/1.957=7,1.957/ 1.957=1, 12.01+1.008+14=27, 102.2/27=3.78 Ans. Empirical Formula – C5H14N2, Molecular – C20H56N8 (c) 59/12.01=4.91, 7.1/1.008=7,26.2/15.999=1.6376, 7.7/14=0.55, 4.91/0.55=8.9,
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