chap10 - further integration

chap10 - further integration - Further investigation of...

Info icon This preview shows pages 1–4. Sign up to view the full content.

View Full Document Right Arrow Icon
Further investigation of integration 1 Chapter 10 Further investigation of integration We have two exceedingly important things to discuss in this chapter: integration over general subsets of R n , and change of variables. We first discuss a characterization of contented sets. A. Topological background We have often hinted at many of the following concepts. It is now time to make certain we understand them completely, and have useful names and notations for them. Recall the definition from Section 3A: if A is a subset of R n and x 0 A , we say that x 0 is an interior point of A if there exists r > 0 such that the ball B ( x 0 , r ) A . A B(x,r) DEFINITION. The set of all interior points of A is called the interior of A , and is denoted int A or int( A ). As we have defined a set to be open if and only if all its points are interior points, we see that A is open ⇐⇒ A = int A . Recall that we proved in Section 3A that the open ball B ( x, r ) is itself an open set. PROBLEM 10–1. Prove that every point of int A is in the interior of int A . That is, int(int A ) = int A . PROBLEM 10–2. The preceding problem shows that int A is an open set. Prove that it is the largest open subset of A , in the sense that if B is an open set and B A , then B int A .
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
2 Chapter 10 PROBLEM 10–3. Prove that int( A B ) int A int B ; int( A B ) = int A int B. Prove that the inclusion expressed above may be a strict one. PROBLEM 10–4. Prove that the union and the intersection of two open sets are also open sets. The notion which is dual to interior will now be discussed. DEFINITION. Let A R n and x 0 R n . Then x 0 is a closure point of A if for every 0 < r < , B ( x 0 , r ) A is not empty. A B(x,r) DEFINITION. The set of closure points of A is called the closure of A , and is denoted cl A or cl( A ). DEFINITION. A set is said to be closed if it contains all its closure points. PROBLEM 10–5. Prove that cl(cl A ) = cl A . PROBLEM 10–6. Prove that the closed ball B ( x, r ) is a closed set. PROBLEM 10–7. Devise the analog of Problem 10–2 and prove the result.
Image of page 2
Further investigation of integration 3 PROBLEM 10–8. Devise the analog of Problem 10–3 and prove the results. PROBLEM 10–9. Prove that the union and the intersection of two closed sets are also closed sets. PROBLEM 10–10. Interior and closure are truly dual notions, for int( R n - A ) = R n - cl A. PROBLEM 10–11. Prove that A is open ⇐⇒ R n - A is closed. WARNING . Don’t misread this problem. A frequent error is to think that a set is open ⇐⇒ it is not closed. We have discussed int A and cl A . A third set will be of great interest to us: DEFINITION. For a given set A R n , the boundary of A is the set bd A = bd( A ) = cl A - int A. PROBLEM 10–12. Let x 0 R n and A R n . Prove that x 0 bd A ⇐⇒ for all 0 < r < the ball B ( x 0 , r ) contains a point belonging to A and also a point not belonging to A .
Image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 4
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern