EntropyExampleProblems - tr Mae: 3 ‘“u.~,www,,« ’...

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Unformatted text preview: tr Mae: 3 ‘“u.~,www,,« ’ ’ 6.10 Answer the following true or false. If false, explain Why. (a) A process that violates the second law of thermody- namics violates the first law of thermodynamics. (b) When a net amount of work is done on a closed system undergoing an internally reversible process, a net heat transfer of energy from the system also occurs. (e) One corollary of the second law of thermodynamics states that the change in entropy of a closed system must be greater than zero or eqnal to zero. (rl) A clo'sed System can experience an increase in entropy - only when lrreversibilities are present Within the sys- tem during the process. (a) Entr0py is produced in every internally reversible pro- cess of a closed system. (f) In an adiabatic and internally reversible process of a closed system, the entrepy remains constant. (g) The energy of an isolated system most remain con- stant, but the entropy can only decrease. a mw‘dam flww .mwmk $9 .$ % .mfli g mé 3mg 3% .éxzaofla P..m駧§ g 3% fig .wm , .mfifi n 3 533%? 9.. 3+ 2% WS .5 gm 43$ 3 anvqu wufigfi HE wgwfi 3 Ti @233wa +3.» m... g u; cakewava Mafigwg 3.1. Qrwmzkkauw .[email protected]fi , x%m..\3k§%c é +U4&~g$h w.“ . Waffi «rm . mmJfiu ficflw 6949 For each of the following systems, specify whether the entropy change during the indicated process is positive. negative, zero, or indeterminate. (a) One kilogram of water vapor undergoing an adiabatic compression process. 4 {h} Two pounds mass of nitrogen heated in an internally reversible process. is} One kilogram of Refrigerant 134a undergoing an adia— batic process during which it is stirred by a paddle wheel. (le One pound mass of carbon dioxide cooled isother— mally. ‘ ’ {a} Two pounds mass of oxygen modeled as an ideal gas undergoing a constant-pressure process to a higher temperature. I {f} Two kilograms of argon modeled as an ideal gas under- going an isothermal process to a lower pressure. .Il'll a “w. - \‘Efi‘! Jagsogh aghwom n w AV . A e. mv d $33 0% Ewéma u Eaéms C? . ‘ \nwwwwiv .hW mEMS .muvdl €5.30???” Wiwkaewfini x+tfiwwguv Ma figufi‘mkfivSQ fiwm. 3H Ammo .wdmxusfl . QAWQ \Om . fiFvow Ffiwhv‘um A CRANK: g.“ . “flxuxM I. HWVOW t. maybe HWQ Q 333$, PW “$.53 . KAI WP « Hafiz Whjwualumwi tafimflOU A» “1.9%gfb MIG“ H. 0.50 @ xllIllllrlnil, . \J Q .. a“ 1W... .... .Qsiktwfi E + Wm. “WAN @ a f newm m0. .flq?§»§+0uu 1.30% AQU A3 .Wmém;usm @334 fiflofi am «‘93:? .ééxufificaxn. , act . he.er d3 Vain—3 VL§+ \ VLWQQ H®3£+ WACFnkW 342W ID? m “mg 0 $42.3 .4de fluxwfi T Patri.” 16 WM. M fiuw .Wwawxué 350% rmoiiw 13+. ~k¢na5¢iv a . a ,r .634 MS“ 3%;wi 3+} mfiigi w {$3 3* . Kg. QWWM umq a 4., .m~&.«\¢>mh Flauasfie... 13.3 Swfiakuz .gsgkwwx WJUJAHI *5 figs-wmfli 3T”... g H .m- onb .35 .bnwfl A“. 92!. "av 058x . a ~ ~. , 5939A. dgéflfiwvfi c6 WY..¢W$CD LflédB may ..m_n‘pJ¢2¢. fififigigmfiso a t 4. M. Vnfifiqu {943w 34+ §x+33 u+4u.€x. «#33 4.26 Law .. Glam .awmwfiufivm hwwwawot. Ofiwasa wfisiwmfi @330 nfifioax “Ru. _. w £quw0wwflm . fiax§§ a 3 + 13 53 ma. \ PROBLEM 6~¥L KNOWN: Dash. avg praw‘dtd M an (admin! tygfg... unn‘xflng a; analuwvsuw‘ W395i. mi, and ltquxd wafer. Finn: D¢4¢rn.‘u£ (a) 4A! Finn! {Emperai‘urt when‘l-kn. 11:41..“ ‘14: can: +6 etiufllbn‘un/ (b) 4km enhapvcktndc {9r 4“»! AWWM Vern], ("he ml, 0AA Wt (c) «u: ans-wad of 2.1m” produced. SCHEMATIcz‘sweu DATA: r _ _ _ ~ w ‘ a _ __~_-; “*1 WW ‘1’“in VCSSe! :mm no.1 k M“me I'M 323 K (32:371.). [0 K5 of ligand wa’O" I'll'h‘nflly “t Tu $393 K k10°cb ‘\\\m\\\ V § Ira liq-m ‘ oil («Udall 1 (xi-TOSRSK (I ll —— _——..~._——_ W5: (0 The szfiem 3509" 1‘“ 4kt attempt-mares: {Usuyg i; is,“f!d, (l) The fluid-WM "st" “*6 0““ 01F A“ Up”! Home: can be modded a: m cowanrble “HA wash” syn-Fit hurt- AWNMW Fm mm M9, “*“eth-F‘ mu «1* Momma: c.9zzr/Ka..»< "a .1: [and ws+lf C.» = 4-. 58 :3/Ic5-K, (“-4 0“ ¢~5‘*‘ 0“ Co 1"- L‘M {bf/L3~K.. {A} \Nr-th ASSUMPfi-gn l ) Q): W : o and a.“ anr’ b“ (Ante redurer a V D D - _ ‘ 0‘ ) \SfLfi-W AU“: flay; (ll/\COMYJMg9 (AU3U+ (GU)°+ (50)“ '-"- O 0.: Ugh” 2V.“ Tm) WHA as: m» ph‘an '3. ‘3: “" WCWLTI; “1111‘ MoCOLTQ “To—1 *’ ““M CHI-T9 ' TM] t O th< Haws-‘6‘?” at: {vb-A MDI: out ivy-"Rd +lmpgm+uvc o.‘ Hun wlyfi-grl W are. ‘1‘“ M‘“ “" I'W'H“ “*nrfium 9} H»: oil..an Mmaudn‘ An. Kc M35. and sud-m. Jyompua‘h r}. GEM»; G¢59¢(fi S0\vliv\% {—or 4‘»: {hat +{mycr;+uff)T+ (b) Ewing; ginger, U;;,\5 E1_5.1‘+(A§SumpHo-a7.} ’ UNA: _, {jaw}? {63) -: was}, Lnngcwxwfin saw; ‘o‘mb‘Hf/K 7 43 i .._,._. I Jo - c l 1‘ :(UUROM m =“0o203‘1 “IV/K -' “‘6 0 -“Ta T} :. (O-IMOA) la 2 ’0'Ooqm ‘ ' a; ‘wr Fa“ ,H‘e r75+{my an can” damage: (C) Sim-o. fihare ii “° have WM” 4" 4° or AS‘M—ba‘ :1» o— : use)“, +(os>o+- (694: T ' b - " K3 W KNOWN“. A 17S‘HM im‘HaHy “Mann, .41 «rivet and mime-pharc. cah‘d-Hqun‘i Math?! a; under a'H-At‘nx an 21v:'|-Brv‘vM shade ad.‘.hu4:‘cn\7 A1” cour+an+ preuure. F’Nbi Duhrw-h-a HM {may +ewrnra-Iuve and flu amounf a-f Quiropy produced. swap-“me 3' GWEN DATA: I I'm'h'all : P “1“‘i‘fi I ’ ’ "‘4 “ kg; : H4- mum, 0.5'Ibn‘vct 53.9 mm _ , Ari mm: Cr - 047. 8+“ Ian/2 “Her :2 33°F 2.5"}: I'ce. .t sz'F ASSUMPTmNS: U) AS 5km” in '1“? acccwpawaiug figure, +kc syshw unis-f: of M , 'H“ i“! ‘iQU‘uJ I 9“" FI‘VF'L (2) C930 4nd pregrure remain: (anxian‘t. (3) The (I'Vft aud \w‘u-d C‘s—n be rejnrded as l‘l’lcowrrfrf'blc Luffh Can ANALYSISISDThC Fina! +emrira+ure can bf dekrmz'neJ tiring an (nervy b‘lanq.‘TAur/ M AU: fl—W, where ngt‘PcIV: pA'V xincg Pram/re is confiunt. S“, AUz—pAV '3) ‘(or 1‘»: CDnSf'uut Presrurt Prom-:1. 7.; an Mac in: an, “at multl+kc 15134.] {eurera fur: would be 32°F. ‘75 fuvcrh‘fa'k’ 41a; '11 T}: be +Ae Fwd +tmrora+urc why. an of flcc :‘te IT fejlrdeci in 1mm Mclkd. 77!”, M14. c: (-0 mum-an $1.1M unufer HM hue 4-195 :——-‘> {Afijtu 1- anti 15 + AHlmua + fierivet : O “ 32°F 31"“"1 what; mow—u T; o * {(1.51b3(t44%) “251m: $00!;— 492)}+ ( em)( nigh) (q- «quagqoaz ‘rgaxtg-mo), 1-; = 4:851”? Smce "Cf CSI'F/ Lt Ca.“ be Concluded fhnf "of all off!” ,‘(9 Mal-h and Hue «from! Ruperahnre u‘: 31°E " o 0’) AV‘ ¢"MP‘/ ‘9‘!“‘9 (2:10am 1‘! give =Jefig); +0' or 0-: AS. 5"an he‘f Ml mf- +he {cg mcHs H u‘: hlfofx‘y.‘ -|o dglfitr-w‘tng, +4“ “MW,” u.” d.” met-L Lgt )u Acnofi'e “a. amour? a? a‘ce Mud MQH’: . 'Tken Since +h¢ “19,11 fem‘fnr ‘14 52 0;] “Ac tutrgy [0;iaute {giver 24 [ Aijce 1- AA n've‘f = o a no; «soo‘F-a Bz’F (“51144 +(o.$lb)(o.nf,_§fi)(4qz— MOPR :0 a) x: 0.7.591“, \Il/ T4 bl’ Rebrm'nj 40 ‘NM. cgleulwh'ou 9-!- 1M: en'ffory Proiuchuh’ 0 U" 1' ASE-“c2 4' £35]th 4“ "TM; éafi'rorr gang? 4 45¢ met um be $9.“: arms 51.6.14, Shy-sink}, A$=ofar Hat h‘qvtd gal 51. (9.14% Smu «Um 4Cmr0r¢gfivyg ramming c¢”9+‘n'f. ch Qn‘h'epy ckAnge {a 4kg met-HIM) (:0. tan b:- fiyud um} 4—112 TdS equa'fi‘wl E7. 6.121,, Muck 51+ mad-curt. precruie aké +€k~Pera+vI€ rfduttr +5 ewg as; 5375. :2) 3;-34' = M'kd. : '443k/Ib :1 0.3727 Bh/Ib'ak ._..a—-—- T m we a— : W M» mama) «mo-mm w ., @.245?}+(~0.oat€) : o. r142. “my/K WWW? KMMV l/Edi} “v-NJ PROBLEM 989* knawN: A“ mulncd Jwbmg at “huh. fine has Hum cum-rag .t I0 bar, (900%,! S0 “[5 "‘4' "VH‘Mf *to'gs “(IMOV‘iLThe Loop-k Jeyc/aped if clarmoc/ *0 bu") ‘°°0 g J/lcjfiua) $00 #3119 . FIDO: Define-nae y; +Ke; claim C‘UK bf Corrfct- > I \ SCHGMA'nc E" filyEN TbATA.‘ a 1 Mt? ‘ 9 40 bar gmmfi' u a i a / L ' T 035‘ mp PM 0 500' P1: onsng T‘19000C’ / v/ .. I ‘(00 W5 % Ifonfs 7‘ W50) TL“: “WWW” operqfes at; Siudj-si-qfc andt‘t‘veun'neulaécd. a) Point-H}! energyj-f/gcfl c‘“ be ffinercd_ w: 4+ S+cd7‘s+‘a "H‘fi e-‘+"’"Y raft balancc reduce; (vi-HA thew-45: Pad: ba|oncc:h3.=h§1=|é fl 5H2. o o ""(sfisth % J 31-h: £2: 20 a. Atarég'm5l3’ Me. c~¢«‘+-I'r\1 npqukg en'h-apy hunt be grader ann/Qre1ual 3 ,‘f‘vl thra‘v «THIN, Spec. fvc. enivupm RM 7...“: 4.4- .+ [0 bow} 000°C , s,:8.02q0 HAWK. The exit speak“ ’enh-opnf +kad‘ urrcsronds +0 ‘Hac chufle‘} Luau-l: Valuc (AK b-g dc'ftvmrned using am Gnlrgu‘ rake ‘cn‘oucc +° fix “an 2_ 7Mslg+ skgdfiq-i-de O ’ o I . I L O—a/adew-i- “(Ln-Judthth +jj2ézfl Edwin, fir, Lx ' aud l'nfi’romfiflg “I ‘5'.“ Tab]: A-4: hlt3bQYuq K’s/K5 L L . 1_ ‘L z 1”“ in: ~83V+ ‘43 ‘F “All = . “JV-‘- upmfl + Pal—.19?” (%)Jl‘xs.fl‘$‘u (asp-u M W 'L =-‘£’f+1m.t% W M) My; 1‘000 mira- ew) we: macaw-Y- W/rv- kavro‘m‘fi“; Thug Adi a 0355er thm HL 3M“ 51:1ng Kalrfi‘K, '5'““‘*"“‘4 +1»; aw”?! vm umr‘sjfii- “M. Lam/{c.fi‘. MW»; 521.: Mama s” 500 knit-3. Ego) 3mm hLuquL'l, naive. Tg+efro‘a+{") “I 431on slfgmm £31534; , Suite 44M“: +9“. C(anmc-Ol valwc «:0de 13¢ (b) Vilma/h; : u; mm; A-‘{ J“ 03be? “’“h‘ valwt is qrcdfif m~$l I, Cal-rt. CI“- PROBLEM (gag, ' , @éfi w: S+¢~d3-s+1+e opu-gh‘nj duh. we prowdecl {or cm cur mac/he. m3 PM": +‘u war-K developed and en‘fropj PA—odbch‘m J gag“ lye, UM was”; u-f: Air +1cwin , VterHS fizz +qrb!n{’ W,‘t kmperafire. SCH‘EMRTLC &, CIVtN fiTPr'. W : {Sen Mys‘c expansfon prca—L expansron no work (2.0.52... W3: “ Tb“ COWJV‘" Vonc- shown. {*1 “Ha-L chmpkfiféy LL’C CS 6” Sk‘é‘x Sin-“'3‘ 2- a? W Can-who! Von:qu Qty-1 D a“: L:h€f\'Q//2o’kK1l|'¢-1 eurgg fika are “3,443,512,. 3.13m“- u; Midas! M an fie»! 3M.4«M3&cam’rmtcwcr. Ava-um: A+ Handy shin] Mars/{her and {n.th mt hummer ,uclurc «affix shkd aSsuwph'OM-S +5 3"” w/Cmmst‘ Wee, 3420913 6 th’ _ h H (.31.; a , W a div: “If; E “_ ~— L _. _' : .3 —-3 CV; fl v --~———---' '2: C XII/1‘22?"— «gm w t J h.“ 1 19 n3 LN I. ‘2. y ,M 1’ h E fir} 5mg; d‘cv/nk "LOJ an. kavc 3; 2.5,, Insch-{M 01C +Kg T‘C CLl'ayr-gm skews +5.4" irk- hwst mugged M}: kwpuaéuvg Cflfl¢rrund$ +1: 52,25, ) {ivwbumk szzo, Sx‘mg spa?~ L ewrbudpa ed- +k- “it "depends ahlg an ‘Hu. 1241,4- kwpcrai-urc (PM 91.: MM , Pmcecs 1—0.. «1w urN:o~un&r +0 1‘”- wan'mwa Mt‘a—l VW-l. 9P \ch/K‘ . The. Mimum “(t #w-qu-J-uJ-o. carru‘mds ‘b‘f‘u C444. Wok-k2 “L: H! (A MW‘M; Wu“), Slur... hLT) ‘97? M ND.“ 345) 444,: are "" P403355 “'C-m M; T1117. W : fiw‘ H’VJS PvafaiamjamL Cg {if “3&6?” okirjremgquafiye. Prams km: 70%?” “2% > “a “'3‘ "2% Wflb“ 673 a ' \ 0‘ __, ,, W U —— A“ ’ E 1 51:33 “'0 7 Cv£“%:fi£“% 9) hill €XV3(CW£M%;) g , L.¢i?5?§u/l§mmvia°fi 32A W 73? CW WEMWM WWW ‘ 71:: 37é99€€2 ~€~Z$0F I Prom 1%: ’L 4 , 5‘01 ‘ P r: a {WM-m” :(0. 0% Bm/awéa ~1~ "" » 3.67 {05) E W FE—QSLEM (22.5” {a 65.5% 3' HQ”! Know”: E‘HEN’H " Sfi’i't “P9N‘H'm3 44% MN: pmw‘ded «For-a. Lyell-fugulnht‘ ”””””””” H dQVL‘LpQ. “YO-ash? 05”“ 5+ I; k““"" “33 'F‘GW M‘f‘fl. FIN-’0: Dckr‘w‘ng dtrecfi‘oy‘ 0% .lll-(‘QW Add M Powgr ("flu-2" a r- and- (mi. (cc-HMA'nc 1: (moan DA’IA ‘. J? "W cm: camjm m a; 5m; Ma Tampa :733K TKS’EQ, Ray/D ' “m” - 30%“; :10 6 mar) Mica K W : [OMS - fimK‘ 5' 1 tmmk r_‘L_s M1; 1 I”.._.-_a—»~»“-~ ASSUMp-rmpqg: (x) The. cmhi VDLUMQ Show" wl +4“ figure: 1‘: act shad: S'ant- C7.) Fina four can'fvm votuw’ Qw 1.0 And ngnfi'q QKFOF3)! «£6an avcfi J- “eglstU-e- (3) A "- u‘s Moi—Lie d an «an *‘da-d gm“. MM? Causfimfi flaé’afic hams, D‘rgbc‘h‘pugh‘fi] 95 a. {pund [W “JPPC-f CS‘CC-rnl). 70%" $3.35qu a ire.” dweuficou Ans-ti n—ppiy an Qua-imp? baianm. Re5w&‘n3 +1.... {4-star 9‘0 £94 §VM i-e-W‘ 4‘3 “KM "'ié I? Ape. 02v .. 32-341 (paw, _ 33' . ‘wf M 1’- b w v\ b00_\ K: = L09 £439 ._ 32:14 4M 5": —- 0.02” --——- C 07 KM” mo 744-7 53% AS ’37“ QAMKD+ U hearth“. n 4"“ ‘LNCHW‘ “’6 flow- fies-HM mewt “few-una- Applu‘rnj 1 ms: and. can mk be. {an to; EXAMPLE PROBLEM An air compressor operating at steady state receives air at p. = 0.95 bar and T, a 22°C. The ratio of the pressure at the exit to the pressure at the inlet is 6. There is no significant heat transfer betWeen the compressor and its surroundings, and kinetic and potential energy changes between the inlet and the exit are negligible. lithe isentro— pic compressor efficiency is 82%, determine the temperaturecf the air at the compressor exit. Use the ideal gas model for air. SOLUTION Known.- Air is compressed from a specified inlet state through a specified pressure ratio. The isentropic compres- sor efficiency is known. Find: Determine the temperature of the air at the exit. Schematic and Given Data: Work input lsentropic compression Figure E6.l4 Assumptions: 1. The control volume shown on the accompanying sketch operates adiabatically at steady state. 2. The changes in kinetic and potential energy between inlet and exit can be neglected. 3. The air is modeled as an ideal gas. Analysis: The temperature at the exit can be determined from the specific enthalpy at the exit. The exit specific enthalpy [2; can be found using the isentropic compressor efficiency ‘ ____ ' ' Mt; t l its r l l - _ i135 ” [it ma- “ _ 222 —— It, Solving for [12 M N M m = m + WW“; I“) ‘3 32. 2 it 12‘; V act/1 tiger/ti,th {C 35'» T 1725 s QM it”; “Renew 7:; sweet) :CM’“ "h t e 77 \ \eizfiétp ’ \ iQ/“i Trig: _..~_ t M ' \PZKR F" a ’1‘" _... 3;” t; wit/fig W. t ,r m l } “k h” " 36026 "[7 liq)? i <6! 9) 5 Comment: Because ofirreversibilities, the compressor requires a greater work input than would be required in an isentropie compression to the specified exit pressure. As shown by the accompanying property diagram, the air exits at a temperature higher than would be achieved in an isentropic compression. WWJ ; PRCBLEM 6.140 w:vs+e‘dv sf‘m oper‘h‘nj dad.“ “re PrDVId‘J {or an air +u-c-bn‘nQ. 5"" WH’K « dam—w» M» H»: emit. 521.”: Dek'm'g- 1'“ Msxt-tf‘» 4"“! chrufi-uf'? 4+ ~H~A fur-l9.“ want and. +5“ Am .1) Qflmpj Mucfiw “IA-m Mbrne’ Show +54” wear»: an a 7-; dingy-M. Santana—dc ‘1 Gwen 34171: We gmnsi‘fé: Wt: BCmKW GD 8‘35"” 42:1 M; l: / a”- - a 727 C d$fmer Dank C Tméé 3"50 AIR \ r33: _ . Hut-“H T M\ Q 7 (wu‘rw/W _ b4!” gch’zfi I t\ I "r " +mme 4- - «. _ ____w - ie :2 mm = loin/s 8/9.9K * ~— -— —. .__,I ‘J‘K‘: V‘: as T, = 727°C 1 M'V‘ s UT: :00 w.[5 WMS: C!) The oven“ confrol vatuw cannsi-r Of +wp Sub COH‘YD‘ Voluwr’ (466‘ af 34—inch? 3+1“. (1)73“: +Larbme ape-rrxf‘tJ AdA‘“bA{1~LAHD‘[3) {:IOW fkycuyla +h€ “WM” “5 "WW‘P‘L M P°"“““" “W7 ‘H‘ch «m be (Jnored- eel/H, olr ‘ Wade kc! OS ah I'dea( figs: gpgcféz eggkwagfixg; a}? m (“E-t a;?*em¥g%$wfifr ANALYSES:®FOI* +Kl. {Stu-iropu‘c pretax: g§rqfr {TM 1% a : Piipa _: ‘ ACCOY‘LS'Ksh") ‘f‘D ‘Gnd P1. MTUIrJJ‘ T1 and T3 ' Hag: 4nd Que??? ruf-Q balance: {or +11: fifty/M pgd’uce +9 film 0 ' ’ V 1 'L ' _ '1 I Gila/‘4'“ *V‘nUI TI? ‘4’” :2 T = ~18t+ +04 4’») W 2 -—3G00 “3/: x * [(100)1-08flzfi‘lfiz) "‘1 It: I )7“ cptarsm+moaKfi Maw/5" (051mm E W ‘ E V J [A ‘ ,_ W I ,, ‘fl 0 :mwmw {0005: I mm»? 44? ~-_.. gmw 5%.4 as” Has: and energy ran-R beddntda: {15v {flak &.f{,«£.¢y—Lred,ucc 11., at.” i. _/ M. L‘ 0‘ [Gary—Av _., V; Upmmfi waxy, ) =2; :3 = h.» v; ~v: ‘ ‘3- LC _ W \3 '3 WWW £22321": 371€H~5< +‘T‘%K 2* «MM: made :13 » 2-‘rfiz%~:'?aa£e ' _ V’ __, :é * 77.7% 7 “M” QR?) - PL=P3{:};: hj (Aber : 0. 45¢ ban 4-wa- w’a ," 32332 (5) PM.” find c.4ij (n+9 bglanCcfi Mince +0 336% {arW-f-«rka'uve {ii-2?:‘iésiasg) ' W344!» E1. Guile. 41a»: ‘38 “M ‘61,; ‘wflcpiém‘Tz/TE‘ «KIMfiIPJ ‘ WW § . ’ w _..__\ g (lacs/SH: m «g QMWCRW .. Exxhfijgjjj E51,: \mas kfiK LOOOK 3” K A . 2 x @3 kw (Iglailafl‘OIZ/fl +0~Wcflk~flzfi~¥< $0; ...
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This note was uploaded on 09/28/2008 for the course ENGRD 2210 taught by Professor Torrance during the Spring '08 term at Cornell University (Engineering School).

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