This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: ChE 2114 First Quiz January 25, 2008
g=9.81n1/s2 or 32.2 an;2 R: 1.8K
l. (25 points) The potential energy of an object at a height h above sorne reference level is given by the familiar relationship PE = rngh. Calculate the potential
energy (in ﬁ'lbf) of a 20.0 pound mass located at a height "F50 feet above the reference level. L (7
v I ' _ :4. '5.
Pt: 3 go 0’32 23fjéz O‘Ct) =1.6ox103ft”9  “9% 2. (25 points) The Weber Number (We) is a dimensionless group useful in the
analysis of certain types of ﬂuid ﬂow. We = pv2Xr’cr Where: p : density of the ﬂuid
v = velocity ofthe ﬂuid
(3 = surface tension, in units of Newtons per meter, Ni’m
X = a quantity with a base unit Using SI units, what is the base unit of the quantity X? W C“; : .
(£75 J
Quantity Equivalent Values
Mass 1kg = 1000 g = 0001 metric ton = 2.204621bn1 = 35.27392 02
111:m = 16 oz = 5 x 10“ ton = 453.593 g = 0.453593 kg
Length 1 m = 100 em = 1000 mm = 106 microns (p.111) ? 1010 angstroms (43L)
= 39.37111. = 3.2808 ft = 1.0936 yd = 00006214111013
11: = 12m. = 1/3 yd = 0.3048m = 30.48 cm
Volume 1m3 = 10001. = 106 cm3 = 106 m1,
= 35.3145 ft3 = 220.83 imperial gallons = 264.17 gal
= 1056.68 qt
1 r13 = 1728111? = 7,4805 gal = 0.028317 m3 = 28.31? L
= 28317 cm3
Force 1N = 1 kgmfsz = 105 dynes = 105 gcmxs2 = 0.2248111)f
111)f = 32.17'4lbmws2 = 4.4482N = 4.4482 x 10ﬁ dynes
Pressure 1 atm = 1.01325 x 105 1916110341) = 101.325 kPa = 1.01325 bar
= 1.01325 x 106 dynesfcmz
= 760 mm Hg at 0°C (torr) = 10.333 rn H20 at 4°C
= 14.696 18016.2 (psi) = 33.9 ft H20 at 4°C
.5 = 29.921 in. Hg at 0°C Energy 1J = lNm = 107 ergs = 10:r dyne‘cm
= 2.778 X 10"? WW: = 0.23901 cal
= 0.7376 ftlbf = 9.486 x 10'4 Btu L.» (30 points) A gas mixture is 200 mass % N2 (MW = 28.0) and 80.0 mass % C02
(MW = 44.0). Calculate the average molecular weight of the gas mixture. {am I (00:28 ——""'O : mwwna
23.0
300 2: LS’ESWCJOA
"i‘ﬁ'O
057V? 2; OAQLMW N; awe+13% _ .
o. '7 l5? aura. M vs : 0.191(za.o)+0.7l9(+4—.o)
3‘— _3‘i. 5.
4. (20 points)
(a) For the relationship PWy = C when lnP (vertical axis) is plotted versus an (horizontal axis) on
rectangular coordinate paper, what is the slope of the resulting straight
line? amen/eucvtmﬂuc
«lb/LP4. (fr/ﬂwvr—‘X/NC,
,e/WP : ‘— %/e/VL\r/ th/awcz 5W?“— Given the relationship between rate constant for a chemical reaction and
absolute temperature: k = Ae'm’mom, where the units of k are W I
second"1 and T is Kelvin temperature. The units of A are (b) If this equation is rewritten using Rankine temperature rather than Kelvin,
k = Aelm), where T is Rankine temperature, the value of X must be 2.] (=00
_ 17.0920 
Jig—4A5, 1’ mpmMW K.
‘x' xlcwm' %K
R = l. &?K
'x = £302,000) I—ZJAOOR L:Af_‘_? ...
View Full
Document
 Fall '08
 PLDurrill

Click to edit the document details