Quiz 1, Sp08

# Quiz 1, Sp08 - ChE 2114 First Quiz g=9.81n1/s2 or 32.2 an;2...

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Unformatted text preview: ChE 2114 First Quiz January 25, 2008 g=9.81n1/s2 or 32.2 an;2 R: 1.8K l. (25 points) The potential energy of an object at a height h above sorne reference level is given by the familiar relationship PE = rngh. Calculate the potential energy (in ﬁ'lbf) of a 20.0 pound mass located at a height "F50 feet above the reference level. L (7 v I ' _ :4. '5. Pt: 3 go 0’32 23fjéz O‘Ct) =1.6ox103ft-”9 - “9% 2. (25 points) The Weber Number (We) is a dimensionless group useful in the analysis of certain types of ﬂuid ﬂow. We = pv2Xr’cr Where: p : density of the ﬂuid v = velocity ofthe ﬂuid (3 = surface tension, in units of Newtons per meter, Ni’m X = a quantity with a base unit Using SI units, what is the base unit of the quantity X? W C“; :- . (£75 J Quantity Equivalent Values Mass 1kg = 1000 g = 0001 metric ton = 2.204621bn1 = 35.27392 02 111:m = 16 oz = 5 x 10“ ton = 453.593 g = 0.453593 kg Length 1 m = 100 em = 1000 mm = 106 microns (p.111) ? 1010 angstroms (43L) = 39.37111. = 3.2808 ft = 1.0936 yd = 00006214111013 11: = 12m. = 1/3 yd = 0.3048m = 30.48 cm Volume 1m3 = 10001. = 106 cm3 = 106 m1, = 35.3145 ft3 = 220.83 imperial gallons = 264.17 gal = 1056.68 qt 1 r13 = 1728111? = 7,4805 gal = 0.028317 m3 = 28.31? L = 28317 cm3 Force 1N = 1 kg-mfsz = 105 dynes = 105 g-cmxs2 = 0.2248111)f 111)f = 32.17'4lbmws2 = 4.4482N = 4.4482 x 10ﬁ dynes Pressure 1 atm = 1.01325 x 105 1916110341) = 101.325 kPa = 1.01325 bar = 1.01325 x 106 dynesfcmz = 760 mm Hg at 0°C (torr) = 10.333 rn H20 at 4°C = 14.696 18016.2 (psi) = 33.9 ft H20 at 4°C .5 = 29.921 in. Hg at 0°C Energy 1J = lN-m = 107 ergs = 10:r dyne‘cm = 2.778 X 10"? WW: = 0.23901 cal = 0.7376 ft-lbf = 9.486 x 10'4 Btu L.» (30 points) A gas mixture is 200 mass % N2 (MW = 28.0) and 80.0 mass % C02 (MW = 44.0). Calculate the average molecular weight of the gas mixture. {am I (00:28 ——""'O : mwwna 23.0 30-0 2: LS’ESWCJOA "i‘ﬁ'O 057V? 2; OAQLMW N; awe-+13% _ . o. '7 l5? aura. M vs :- 0.191(za.o)+0.7l9(+4—.o) 3‘— _3‘i. 5. 4. (20 points) (a) For the relationship PWy = C when lnP (vertical axis) is plotted versus an (horizontal axis) on rectangular coordinate paper, what is the slope of the resulting straight line? amen/eucvtmﬂuc «lb/LP4. (fr/ﬂwvr—‘X/NC, ,e/WP : ‘— %/e/VL-\r/ th/awcz 5W?“— Given the relationship between rate constant for a chemical reaction and absolute temperature: k = Ae'm’mom, where the units of k are W I second"1 and T is Kelvin temperature. The units of A are (b) If this equation is re-written using Rankine temperature rather than Kelvin, k = Aelm), where T is Rankine temperature, the value of X must be 2.] (=00 _ 17.0920 - Jig—4A5, 1’ mpmMW K. ‘x' xlcwm' %K R = l. &?K 'x = £302,000) I—ZJAOOR L:Af_‘_? ...
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• Fall '08
• PLDurrill
• Kilogram, base unit, gas mixture, Rankine temperature, familiar relationship PE, Quantity Equivalent Values

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Quiz 1, Sp08 - ChE 2114 First Quiz g=9.81n1/s2 or 32.2 an;2...

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