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Unformatted text preview: Quiz #1 Chem 3615- Physical Chemistry Instructor: Esker September 4, 2008 NAME:__Answer Key___________ Score = 40 + _____ x 15 = ________ Useful Information: pV = nRT, R = 8.314 Jmol-1K-1 = 0.08206 Latmmol-1K-1, 1 atm = 760 mm Hg = 760 Torr = 101325 Pa, 0.001 m3 = 1 L = 1000 cm3, dW = - Fdz = -popdV, Euler's Formula x y z 1 V 1 V nRT an 2 , dU = dQ + dW, H = U + pV, = -1 , p = , = - , =- y z (V - nb ) V 2 V p T V T p z x x y T U H -1 CV = = constant, pV = constant, p1- T = , Cp = , JT = , dS = dQ/T, TV p T V T p H constant, = Cp/Cv, G = H-TS, A = U-TS Circle the correct letter. If you change your mind, make sure the original answer is completely erased. If you are using a pen, black out a wrong answer completely 1. 1.00 mol of an ideal gas in a 22.4 L vessel has a temperature of 25 C. What is the numerical value of the coefficient of thermal expansion using the appropriate SI units? (a) 9.04 x 10-6 (b) 3.36x10-3 (c) 0.040 (d) 0.917 . 2. Nine metal blocks, initially at different temperatures, TA, TB, TC, TD, TE, TF, TG, TH and TI, are isolated from the surroundings by an adiabatic wall. The walls between blocks A and B, D and E, E and F, G and H, and H and I are adiabatic. All other walls between blocks are diathermic. Note that corners (diagonal contacts) do not count, only the four walls around a given block should be considered. TA = TD= TG A B C TB = TC = TE =TF =TH =TI (e) 1.09 D E F G H I Indicate which of the following must be true at equilibrium or that none of them are true: (a) TA = TI MAYBE (b) TG = TE MAYBE (c) TC > TH FALSE (d) TI < TD MAYBE (e) None of them must be true MAYBE = could be true, but it could also be false. We cannot tell without further information. Page 1 of 2 3. If you have 1 x 104 mol of an ideal gas in a 22.4 x 10-3 m3 sealed container at 273 K, what is the pressure? (a) 1 mPa (b) 1 cPa (c) 1 kPa (d) 1 MPa (e) 1 GPa . 4. Indicate which of the following graphs must be incorrect for a perfect gas or that they are all correct. (a) True (b) True p T . 0 0 p 0 0 _ V / / Hence, vs. T is a hyperbola. (c) True
p _ V / Hence p vs. yields hyperbolae. As T decreases, the constant decreases and the hyperbola shift closer to the origin. (d) True _ V
p 0 -273.15 0 T /deg. C 0 T /K Hence, the slope increases as decreases!!! Hence, the slope decreases as p increases!!! (e) All of the above are correct
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