exam2 - EEE EDS: Exam 2 Much 28, 201]? Name: SID LUTIGMS AS...

Info iconThis preview shows pages 1–6. Sign up to view the full content.

View Full Document Right Arrow Icon
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 4
Background image of page 5

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 6
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: EEE EDS: Exam 2 Much 28, 201]? Name: SID LUTIGMS AS UID: Thia is a, closed book, nlnsed notes ear-Lam. You are aliuwcd one (heat—sheet. For qu credit1 ShUW all fit-EDS. Good Luck] 1. Determine the Fourier series representation of the signal mft} = {sin t}{ene 3t). , Lit 4‘5 KIM/"Q :2 ’1J . 4'3: 43* ngat a Q 4'3 2— , . (4+ e-e’¢< _"t M31) x * [AW X 2d. } J41: xiii" -.: .1— ‘9. +Q "" e 4. J kapt 5 261406 -r-'.- 0‘2: 4J a J.— mu-m' 4} e ele- “4 4J l n a -*—-.* #4 41 2. Consider an LTI system with the impulse respuuse Mt) = cguf—t}. 'tht is the output yfi} if the input is was It? Kl: ‘t —_]t J 7r{_{): (Lost {fl 1. game wazi '2 K (11: H2. flirylitfl t l~ - = A; a) “4 gr x: .{jk'wa’l' Hfijjkmo); f e LAC-$342. rue 0 F2: tr'lcmo : f e t 4 36m w, I D artLJerLflu} f- I :2- l—rJKC-J‘fl _ rail HQKL—L—Hk IN 4 SCH—"EWHGWE 1t "HI = cut __i‘ edt + Old—11:13 [—J —'t I ¢ 493+ #8. ‘J ) '2 l—J H'J H m 8 n ,4. J In § H" J cs?“ 31:1} A continuous time signal mfit} has the following Xfiw}. What is fit}? XCJWJ b a. b ><(.;aw>=a9(w>+b9(m-2> #2. o 9. W +bg£m+2> ‘52Jc “‘3({Jc)=_L o-l*béifit+bflJ j '2’“ til/2&0 +T_’Irl'éoo(lt {b} The Fourier Transform of y{t} is YUM} = Sonatina — 10). What is: yfii)? ‘ZTI sorocofi é-—‘:-' th’rTJ—“Ctflrro H jg“ Lox (“t-k0 # Unfit ‘0] Sim: oo goanCco—m) 4—» gilot [ufiflj— UCf F0] '7. q: HR! 0 4. Consider the AM systEm shown in the figure below. {a} What is Yfiw) ifmit} = Efihsimfmt}? Assume w: :5} ma. Sketch ijw}. {b} What is Efjw]? Sketch Efjw}. (Hint: £0323 = {I + maEflHDf‘E.) :fi‘ft5 KG) ._-y,{?—av . .. fig 26,) #9 casth anew; Esme Ht é—‘s- “(m+w)_m(m-w) 6.? 2g! Imftf‘w Tr 0 GW '2 m|<=Cfi¢u=n git-LIED 5mc-mbt H QEWCw+wb>- U(b3'm|g)] M. ED L . \. (at) XUH] -9310 .9 mb' ‘0 [b] 20;]: q(£)m£mff : T(+}[I+cog‘2pdcf] '2. l+wgflmci EH- 27T5;(c.a) + TT(m-‘2wc) +TT(¢J+2%) ZCJLAJ) 1 a; Ezfl’g(m) +fi(m-‘2w¢) +TT (w+2mc:|] -: KO“) + $X6J(cni—2Wc))+z1ix<j(cm+'2wc)) 2 :09:- 3 '33. y:- 53 . “‘ch flab a Dob 1&1:an 203C ‘Mfiffidb 5~ The impulse response nf an LT] s ' - w _ ystemmgwenb ht='-bt _ '3 git) If the input fit} = train“)! a 3, fl? 3 I: J F “Wm '5 3' Or What 15 tha output Ea: “Pb; [Extra credit: What is the output yfi} if a = b?) H3190? d- —- .1 1 K94 J {ff—'3?qu X '50 :: I G ) al+\fflfi} :_ vim—mfi _—. B W (bwww) WM W, A " 2 .L— biilw 9.4;}me 5'0” B = 4—1 a 4— &flw 1b+Jwro 0"” b _J._. \‘(ij = 5‘0” "' “1 +JW b+dlw _ —- “f v- Hmfif Le a“ -— e “I U~00 ...
View Full Document

Page1 / 6

exam2 - EEE EDS: Exam 2 Much 28, 201]? Name: SID LUTIGMS AS...

This preview shows document pages 1 - 6. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online