chem6 - Experiment 6- Determination of an Equilibrium...

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Experiment 6- Determination of an Equilibrium Constant Pre-Lab Questions 1. A. Equilibrium is on the product side, therefore the product side is more concentrated than the reactant side. B. Equilibrium lies on the reactant side, the reactant side is more concentrated than the product side. 2. K=[Fe(SCN)2+]/[Fe3+][SCN-] 3. B= thickness of the absorbing sample in centimeters C= concentration of the sample in moles/L E= the molar absorbtivity coefficient in units of L mol-1 cm-1 Io= intensity of the incident light Ie= transmitted light 4. Combination of a light brown solution containing iron (III) nitrate, Fe(NO3)3 with a colorless solution containing potassium thiocyanate, KSCN then measure the absorbance A and calculate the concentration c using the relationship , c=A/eb. 5. Calibration line allows us to determine equilibrium concentrations of Fe(SCN)2+ by measuring the absorption . Eb is determined by plotting absorbance as the function of Fe(SCN)2+ concentration and the slope of the line gives you the value eb. 6. We use equal concentrations so that equilibrium can be taught and the equation will not shift too far to the right or the left. The equilibrium concentration of Fe(SCN)2+ is determined from the calibration line. The wavelength of 450 is used so that only the product concentration will be recorded. 7.
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This note was uploaded on 09/30/2008 for the course CHEM 1A/1B taught by Professor Neuman during the Fall '06 term at UCSB.

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chem6 - Experiment 6- Determination of an Equilibrium...

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