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chem3 - Experiment 4 Determination of a Chemical Formula...

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Experiment 4- Determination of a Chemical Formula Pre Lab Questions 1. In forming compounds, a calcium atom loses 2 electrons. The charge on the hydroxide ion is -1. For the chemical formula of calcium hydroxide, it will equal Ca(OH)2. No, calcium hydroxide does not have a charge. 2. 2Na + 2H20 > 2NaOH + 1H2 2Na + 2HCl > 2NaCl + 1H2 3. 15.0 g Na x (1 mol Na/22.99 g Na)x(1 mol H2/2 mol Na)= 0.326 mol H2 4. A) OH- + H+ > H20 B) The reaction is complete when there is a change in the physical property. 5. A) [H+]>[OH-] The solution is acidic B) [H+]<[OH-] The solution is basic C) [H+]=[OH-] The solution is neutral 6. HCl + KOH > KCl + H20 HCl + Ba(OH)2 > BaCl2 + H20 Introduction The purpose of the lab is to see what happens when metals react with water and acids. Also, to use the acid-base titration as a method to determine the molecular formula of a compound. Data Part 1 1. The first part of step 1 was to put 2mL of 6M HCl in a clean test tube. Then add zinc to the test tube and place it over the first at an angle. The following table involves adding HCl and water to Calcium and Zinc and writing down the observations. Reactants Observations Zn+6 M HCl I noticed it bubbled upward and emitted H2. Then the water turned white. There was no precipitate.
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Ca+0.02 M HCl The tube got hot and that caused the CaCl solution to precipitate. Zn+water Nothing occurred and the solution stayed stable.
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