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4605Solnf08-04 - 4 2.3-1(old notes Rs=2000 C L R2=50...

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6 4605Solnf07.wxp L C R 2 =50 Ω R s =2000 Ω R t =1000 Ω 4. 2.3-1. (old notes) a. Determine and for MHz. P G 0 œ "! 9 b. Determine the bandwidth (in Hertzian units). F ================================ = 1 9 ( œ # ‡"! œ 'Þ#)$‡"! MHz r/s a. The transformation is from 50 to 1000. This gives ;  " œ œ #! Ê ; œ "* œ %Þ$&)*
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