calassignment 3-solutions

calassignment 3-solutions - miller(zdm77 assignment 3...

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miller (zdm77) – assignment 3 – luecke – (58600) 1 This print-out should have 15 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. 001 10.0 points Which one oF the Following conic sections has graph 1 2 1 2 1 2 3 1 1. y 2 + 2 y + x 1 = 0 2. x 2 + 2 x + y 1 = 0 3. x 2 2 x + y 1 = 0 4. y 2 + 2 y x 1 = 0 5. y 2 2 y + x 1 = 0 correct 6. x 2 2 x y 1 = 0 7. y 2 2 y x 1 = 0 8. x 2 + 2 x y 1 = 0 Explanation: The graph is that oF a parabola opening to the leFt and having vertex at (2 , 1). Thus it is the graph oF ( y 1) 2 = A ( x 2) , For some A > 0. But the graph also passes through (1 , 2), so A = 1. Consequently, the graph is that oF the conic section ( y 1) 2 + x 2 = 0 , which aFter expansion and simplifcation can be rewritten as y 2 2 y + x 1 = 0 . keywords: graph, conic section, parabola, shiFted parabola, 002 10.0 points ±ind an equation For the parabola having vertex (0 , 0) and Focus (0 , 2). 1. x 2 = 3 y 2. x 2 + 8 y = 0 correct 3. x 2 = 8 y 4. x 2 + 2 y = 0 5. x 2 = 2 y 6. x 2 + 3 y = 0 Explanation: The parabola with equation x 2 = 4 ay has Focus (0 , a ) and vertex (0 , 0). Conse- quently, when a = 2, the parabola has equa- tion x 2 + 8 y = 0 . 003 10.0 points ±ind an equation oF the ellipse. Then fnd its Foci. 4 8 4 8 4 8 4 8 x y
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miller (zdm77) – assignment 3 – luecke – (58600) 2 1. x 2 64 + y 2 49 = 1, foci: p ± 15 , 0 P 2. x 2 49 + y 2 64 = 1, foci: p 0 , ± 15 P correct 3. x 2 49 + y 2 64 = 113, foci: p 0 , ± 15 P 4. x 2 8 + y 2 7 = 1, foci: p ± 15 , 0 P 5. x 2 7 + y 2 8 = 1, foci: p 0 , ± 15 P Explanation: keywords: 004 10.0 points Find the vertices, foci and asymptotes of the hyperbola 2 x 2 3 y 2 + 24 x 30 y = 9 . 1. vertices: p 6 ± 3 , 5 P , foci: p 6 ± 5 , 5 P , asymptotes: y + 5 = ± r 2 3 ( x + 6) correct 2. vertices: p 6 ± 3 , 5 P , foci: p 6 ± 5 , 5 P , asymptotes: y + 5 = ± r 3 2 ( x + 6) 3. vertices: p 6 ± 3 , 5 P , foci: p 6 ± 5 , 5 P , asymptotes: y 5 = ± r 2 3 ( x + 6) 4. vertices: p 6 ± 5 , 5
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calassignment 3-solutions - miller(zdm77 assignment 3...

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