w8-04 - ds 2 = 2 + 2 + 2 ds 2 = 2 + 2 + 2 + 2 c = 299 - 79...

Info iconThis preview shows pages 1–9. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ds 2 = 2 + 2 + 2 ds 2 = 2 + 2 + 2 + 2 c = 299 - 79 - 2458 -1 ds 2 = 2 + 2 Minkowski Special Relativity: 1908 Sep 21 ds 2 = + ( 29 ( 29 + ( 29 ( 29 + ( 29 ( 29 + ( 29 ( 29 dX = dY = dZ = ds 2 = + ( 29 ( 29 + ( 29 ( 29 + ( 29 ( 29 + ( 29 ( 29 ds 2 = - 2- 2- 2 + 2 2 ds 2 = - 2- 2- 2 + 2 ds 2 = 2 + 2 + 2- 2 2 Chapter 3, #12 6 CLICKER QUESTIONS For the vectors and a = 3.0 ( 29 + 4.0 ( 29 b = 5.0 ( 29 +-2.0 ( 29 1) give a + b in unit-vector notation 2) give a + b as a magnitude 3) give a + b as a direction relative to i 4) give b- a in unit-vector notation 5) give b- a as a magnitude 6) give b- a as a direction relative to i ion in Two and Three Dimensions Motion in Two and Three Dimensions x y z r r 1 r r 2 r ur u ion in Two and Three Dimensions Displacement Vector r x y z r r 1 r r 2 r ur u r r 2 = 1 + r ur u = r r 2- r r 1 = x 2 i + y 2 j + z 2 k ( )- x 1 i + y 1 j + z 1 k ( ) = x 2- x 2 ( ) i + y 2- y 2 ( ) j + z 2- z 2 ( ) k r ur u = D x i + D y j + D z k ion in Two and Three Dimensions Average velocity & Instantaneous velocity r v avg = = + + = + + x y r r r v = ion in Two and Three Dimensions Average acceleration & Instantaneous acceleration r a = r a avg = = 2- 1 r a = = + + ( 29 = + + a x = , = , = , To find the scalar components of a , differentiate the scalar components of v ion in Two and Three Dimensions Chapter 4, #19 The acceleration of a particle moving only on a horizontal x , y plane is given by where a is in m/s/s and time t is in seconds. r = 20.0 ( 29 + 40.0 ( 29 At t = 0, the position vector locates the particle, which then has the velocity vector v = 5.0 / ( 29 + 2.0 / ( 29 At t = 4.00 s, what are a) its position vector in unit vector notation b) the angle between its direction of travel and the positive direction of the x axis? The motions in x , and y , are independent! a = 3 + 4 a = 3 + 4 a = 3 + 4 THIS IS NOT A CONSTANT ACCELERATION PROBLEM! d 2 x d t 2 = 3 d 2 y d t 2 = 4 dy d t = 4 2 2 + 2 = 34 dx d t = 3 2 2 + 5 = 29 x = 3 2 3 3 + 5+ 20 = 72 y = 4 2 3 3 + 2+ 40 = 90.67 r = 72.0 ( 29 + 90.67 ( 29 ion in Two and Three Dimensions Chapter 4, #19 b) the angle between its direction of travel and the positive direction of the x axis?...
View Full Document

Page1 / 77

w8-04 - ds 2 = 2 + 2 + 2 ds 2 = 2 + 2 + 2 + 2 c = 299 - 79...

This preview shows document pages 1 - 9. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online