Stats - SD = √ pq/n = √(0.30(0.70(300 = 0.491 Mean = 30...

Info icon This preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Stats Chapter 18 6. 500 candies 12%= green p= 0.12 np = 500 (0.12) = 60 >10 nq = 500 (0.88) = 487 > 10 SD = √ pq/n = √(0.12)(0.88) / (500) = 0.0167 N(0.12, 0.167) This is a not a large proportion because the proportion falls within one standard deviation of the mean. With the sample size exceeding more than 100, it suggests that the probability of sustaining one color will nearly be fewer than 15 percent. This is certainly a reasonable probability. 10. 30% students at a university wear contact lenses. a) P = 0.30 Sample size = 100 p(hat) = 3.34% Np= 300(.30) = 30 <10 Nq= 300(.70) = 210.2 >10
Image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: SD = √ pq/n = √(0.30)(0.70) / (300) = 0.491 Mean = 30% SD = 0.491 Assume that the students of the university either wear contacts, glasses, or don’t at all. The probability of them wearing contact lenses is near a fourth of the sample size. The random sample of students represents the less 10% possibility of the students wearing contact lenses. Np = .30 and nq= 210.2 are at least both ten. b) The appropriate probability that more than one third of the sample wears contacts is .033. It is small because the sample size is relatively small....
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern