Stats - SD = √ pq/n = √(0.30(0.70(300 = 0.491 Mean = 30...

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Stats Chapter 18 6. 500 candies 12%= green p= 0.12 np = 500 (0.12) = 60 >10 nq = 500 (0.88) = 487 > 10 SD = √ pq/n = √(0.12)(0.88) / (500) = 0.0167 N(0.12, 0.167) This is a not a large proportion because the proportion falls within one standard deviation of the mean. With the sample size exceeding more than 100, it suggests that the probability of sustaining one color will nearly be fewer than 15 percent. This is certainly a reasonable probability. 10. 30% students at a university wear contact lenses. a) P = 0.30 Sample size = 100 p(hat) = 3.34% Np= 300(.30) = 30 <10 Nq= 300(.70) = 210.2 >10
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Unformatted text preview: SD = √ pq/n = √(0.30)(0.70) / (300) = 0.491 Mean = 30% SD = 0.491 Assume that the students of the university either wear contacts, glasses, or don’t at all. The probability of them wearing contact lenses is near a fourth of the sample size. The random sample of students represents the less 10% possibility of the students wearing contact lenses. Np = .30 and nq= 210.2 are at least both ten. b) The appropriate probability that more than one third of the sample wears contacts is .033. It is small because the sample size is relatively small....
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This note was uploaded on 10/02/2008 for the course ILRST 2100 taught by Professor Vellemanp during the Fall '07 term at Cornell.

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