Tarea 3

Tarea 3 - H 6 30g 1 mol C 2 H 5 Cl C 2 H 6 125g 4.17 mol C...

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2 Al(OH) 3 + 3 H 2 SO 4 Al 2 (SO 4 ) 3 + 6 H 2 O 2 Al(OH) 3 154g Al 2 (SO 4 ) 3 342g 3 H 2 SO 4 294g 6 H 2 O 108g 2 Al(OH) 3 Al 2 (SO 4 ) 3 0.5 Al(OH) 3 0.25 Al 2 (SO 4 ) 3 3 H 2 SO 4 Al 2 (SO 4 ) 3 0.5 H 2 SO 4 0.167 Al 2 (SO 4 ) 3 H 2 SO 4 es el reactivo limitante Al 2 (SO 4 ) 3 100% 0.167 Al 2 (SO 4 ) 3 16.7% Al(OH) 3 154g 100% Al(OH) 3 154g 100% Al(OH) 3 25.718g 16.7% Al(OH)3 38.5g 25% Se pueden formar 0.167 moles de 0.167 Al 2 (SO 4 ) 3 y de reactivo en exceso después de la reacción sobraran 12.79 gramos de Al(OH) 3
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C 2 H 6 + Cl 2 C 2 H 5 Cl + HCl C 2 H 6 30g C 2 H 5 Cl 64g Cl 2 70g HCl 36g C 2
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Unformatted text preview: H 6 30g 1 mol C 2 H 5 Cl C 2 H 6 125g 4.17 mol C 2 H 5 Cl Cl 2 70g 1 mol C 2 H 5 Cl Cl 2 255g 3.64 mol C 2 H 5 Cl 3.64 mol C 2 H 5 Cl 232.96g 100% C 2 H 5 Cl 206g 88.42% El rendimiento de la reaccin terico es de 3.64 moles son el 100%. Y el rendimiento practico de la reaccin para que de 206 g debe de ser de 88.42%...
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Tarea 3 - H 6 30g 1 mol C 2 H 5 Cl C 2 H 6 125g 4.17 mol C...

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