Exam2CKey

Exam2CKey - 1 Consider the following reaction 2 HBr(g Cl2(g...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
1) Consider the following reaction: 2 HBr(g) + Cl 2 (g) ¾ 2 HCl(g) + Br 2 (g) At the reaction temperature of 350 K, K = 1.1 x 10 3 . During the reaction, the reaction mixture was sampled and the following pressures were found: P(HBr) = 0.084 atm P(Cl 2 ) = 0.11 atm P(HCl) = 0.63 atm P(Br 2 ) = 0.75 atm a) (15) What is the value of Q? Q = = = (0.11) (0.084) (0.75) (0.63) ) P(Cl P(HBr) ) P(Br P(HCl) 2 2 2 2 2 2 380 b) (15) What is the value of G at the reaction temperature? G = RT ln(Q/K) = (0.00831) (350) ln (380 / 1.1 x 10 3 ) = -2.6 kJ c) (10) Does this reaction proceed to the left or right to get to equilibrium? right 2) (10) Consider cases A and B below, where each will have the same number of molecules at the same temperature: 0 2 4 6 E 0 2 4 6 E A B Which case has the greater entropy, and why? A has the greater entropy. The greater density of states allows for a greater number of ways that the energy can be distributed.
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
3) (15) Given the following enthalpies of reaction: (a) H 2 (g) + 1 / 2 O 2 (g) ¾ H 2 O(g) H = -242 kJ (b) 3 O 2 (g) ¾ 2 O 3 (g) H = +285 kJ Calculate the enthalpy change for the following reaction:
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 10/03/2008 for the course CH 201 taught by Professor Warren during the Spring '07 term at N.C. State.

Page1 / 4

Exam2CKey - 1 Consider the following reaction 2 HBr(g Cl2(g...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online