Exam2DKey

# Exam2DKey - 1(15 Write a balanced chemical equation for the...

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1) (15) Write a balanced chemical equation for the reaction that corresponds to the heat of formation of one mole the amino acid glutamic acid, C 5 H 9 NO 4 . 5 C(s) + 9 / 2 H 2 (g) + ½ N 2 (g) + 2 O 2 (g) b C 5 H 9 NO 4 2) (15) Given the following: 2 Mg(s) + O 2 (g) b 2 MgO(s) H = - 1204 kJ What is the enthalpy change when 5.70 g of MgO react to form Mg and O 2 ? 5.70 g MgO x MgO g 40.31 MgO mol 1 = 0.1414 mol MgO (-1) x MgO mol 2 kJ 1204 - x 0.1414 mol MgO = +85.1 kJ 3) (15) Given the following enthalpies of reaction: (a) 4 H 2 (g) + O 2 (g) + 2 C(s) ¾ 2 CH 3 OH (l) H = - 402 kJ (b) 2 CO(g) ¾ 2 C(s) + O 2 (g) H = +220 kJ Calculate the enthalpy change for the following reaction: CH 3 OH(l) ¾ CO(g) + 2 H 2 (g) ½ x (-a) : CH 3 OH (l) ¾ 2 H 2 (g) + ½ O 2 (g) + C(s) H = + 201 kJ ½ x (-b) : C(s) + ½ O 2 (g) ¾ CO(g) H = -110 kJ CH 3 OH(l) ¾ CO(g) + 2 H 2 (g) H = (+201) + (-110) +91 kJ 4) (15) A sample of titanium (specific heat = 0.52 J/g- o C) was removed from an oven at 325.00 o C. It was placed into a Styrofoam cup with 175 g of water at 24.07 o C. The temperature equilibrated at 27.25

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## This note was uploaded on 10/03/2008 for the course CH 201 taught by Professor Warren during the Spring '07 term at N.C. State.

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Exam2DKey - 1(15 Write a balanced chemical equation for the...

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