homework2_q1 - Dv10-3s=110m The electron energy is...

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Sheet1 Page 1 Problem 1, solution It travels 2km in ~10-3s. The initial uncertainty in its position is Dx=10-9m. After 10-3s the uncertainty in its position is on the order of
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Unformatted text preview: Dv10-3s=110m. The electron energy is E=10eV=1.6h10-18J. Its speed is v=(2E/m)1/2=1.88h106m/s. Dp=h/Dx, Dv=h/(mDx)=1.1h105m/s....
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This note was uploaded on 10/05/2008 for the course ECE 221 taught by Professor Marthapardavi-horvath during the Spring '08 term at GWU.

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