More Examples Sec 12.4

More Examples Sec 12.4 - k 2 1.86667 â k = 1 ¥ 1 Cos k D...

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A and B converge by comparison. (B) Is geometric with r <1, converges.
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1 + cos H k L k 2 < 2 k 2 à k ¥ 2 x 2 â x 2 k So R k < T k < 2 k Now R 10 < T 10 < 2 10 So the error is at most 1/5. Let’s check on Mathematica: â k = 1 10 1 + Cos @ k D
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Unformatted text preview: k 2 1.86667 â k = 1 ¥ 1 + Cos @ k D k 2 1.96907 Take the difference between 1.96907 and 1.86667, .1024 which is less then our upper bound of 1/5....
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More Examples Sec 12.4 - k 2 1.86667 â k = 1 ¥ 1 Cos k D...

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