This preview shows pages 1–3. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.View Full Document
Unformatted text preview: EE40: Introduction to Microelectronic Circuits Homework One Solutions September 28, 2008 Due at 5 pm in 240 Cory on Friday, 9/12/2008 Total Points: 100 Put (1) your name and (2) discussion section number on your homework. You need to put down all the derivation steps to obtain full credit for each problem. No late submission will be accepted unless approved by the instructor. Problems of this HW are from Hambley 4th Edition. Each problem is worth 10 points. 1. Hambley, P1.7 Charge per electron is -1.6 E-19 C. Current of 1 A flows, carried by elec- trons. Find number of electrons that pass through a cross section of the wire per second. Recall current, [A] is [C / sec] which can be rewritten as [(C / electron) * (electron / sec)] 1 A = 1 (C / electron) * (electron / sec) So electrons / sec = 1 / (C/electron) = 1/ (1.6E-19) = 6.25 E18 Electrons – 6.25 E18 Note: Signs were ignored since we don’t care about the direction for this problem. However, remember that electrons have negative charge so they would flow against the direction of current. 2. Hambley, P1.9 v = 12 [V], i ba = -2 [A] v = v ab i = i ab =- i ba = -(-2 [A]) = 2 [A] 1 2 v ba = -12 [V] i = 2 [A] The energy is delivered to the element: P element = v ba * i ba = -12 [V] * -2 [A] = 24 [W], so energy is delivered to the element....
View Full Document