Exercise 1

# Exercise 1 - Jonathan Church JC8975 BIO 205L: Exercise 1...

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Jonathan Church JC8975 BIO 205L: Exercise 1 Analysis 1. 100 mL beaker Mean – (57.82 + 59.23 +58.60 + 59.18 + 59.33 + 56.09 + 55.61 + 59.58 + 60.61 + 59.71 + 58.54 + 58.69 + 57.95 + 54.59 + 58.45 + 59.45 + 57.55 + 55.61 +55.48 + 53.81 + 59.76)/ 21 = 57.89 mL Percent Error – (60 mL - 57.89 mL)/60 mL = 3.52% Standard Deviation – sqrt(((57.89 – 57.82)^2 + (57.89 – 59.23)^2 + (57.89 – 58.6)^2 + (57.89 – 59.18)^2 + (57.89 – 59.33)^2 + (57.89 – 56.09)^2 + (57.89 – 55.61)^2 + (57.89 – 59.58)^2 + (57.89 – 60.61)^2 + (57.89 – 59.71)^2 + (57.89 – 58.54)^2 + (57.89 – 58.69)^2 + (57.89 – 57.95)^2 + (57.89 – 54.59)^2 + (57.89 – 58.45)^2 + (57.89 – 59.45)^2 + (57.89 – 57.55)^2 + (57.89 – 55.61)^2 + (57.89 – 55.48)^2 + (57.89 – 53.81)^2 + (57.89 – 59.67)^2)/20)) = 1.92 95% Confidence values – 1.92 x 2 = 3.84 57.89 + 3.84 or 57.89 – 3.84 5 mL Pipet Mean - (4.13+4.16+4.01+4.18+3.84+3.88+3.90+3.95+4.18+4.11+4.33+4.17+4.21+4.19+3.93+3.86+4.01 +4.05+4.96+3.85+3.98)/21 = 4.09 mL

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## This note was uploaded on 10/12/2008 for the course BIO 205L taught by Professor Hanson during the Fall '07 term at University of Texas.

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Exercise 1 - Jonathan Church JC8975 BIO 205L: Exercise 1...

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