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Bio exercise 2

# Bio exercise 2 - Jonathan Church JC8975 BIO 205L Exercise 2...

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Jonathan Church JC8975 BIO 205L: Exercise 2 1a. Mean length = (21.0 + 16.0 + 17.0 + 16.5 + 14.0)/5 = 16.9 r.u. Mean Width = (5.0 + 4.5 + 5.0 + 5.0 + 5.0)/5 = 4.9 r.u. 1b. Standard Deviation Length = sqrt(((21-16.9)^2 + (16-16.9)^2 + (17-16.9)^2 + (16.5-16.9)^2 + (14- 16.9)^2)/4) = 2.559 Standard Deviation Width = sqrt(((5-4.9)^2 +(5-4.9)^2 +(5-4.9)^2 +(5-4.9)^2 +(4.5-4.9)^2)/4) = 0.223 1c. Length - 2.559 x 2 = 5.118, so 95% confidence levels are 16.9 + 5.118 or 16.9 - 5.118 Width – 0.223 x 2 = 0.446, so 95% confidence levels are 4.9 + 0.446 or 4.9 – 0.446 2. To approximate the volume of a paramecium, I would use the volume of a rectangular prism. I believe the Paramecium’s shape most closely resembles a rectangular prism, however the estimated volume will be larger than the real value due to the smooth round ends of the paramecium. The equation for the volume of a rectangular prism is Volume = Length x Width x Height. When using this equation, we will assume that the paramecium has equal width and height. 16.9 r.u. x 9.8 µm/1 ru = 165.62 µm 4.9 ru x 9.8 µm/1 ru = 48.02 µm Volume = 165.62 x 48.02 x 48.02 = 381,906.54 µm 3 or 381.91 mm 3 3. SA = 2LW + 2LH +2 WH = 2 x 48.02 x 48.02 + 4 x 165.62 x 48.02 = 36,424.13 µm 2 or 36.424 mm 2 4. S/V = 36.424 mm 2 /381.91 mm 3 = 0.0954 mm -1 5a. The Microscope has a built in Illuminator.

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Bio exercise 2 - Jonathan Church JC8975 BIO 205L Exercise 2...

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