chandra_324_hw1_soln

chandra_324_hw1_soln - ME324 Sec. D - Solution for HW 1 1....

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ME324 Sec. D - Solution for HW 1 1. Not true for the compression test. true stress: , A is the true area of the material. Engineering stress: , A 0 is the original area of the material. Assumption : Keeping volume constant. we have: During tension test, , true stress is greater than engineering stress. During compression test, , true stress is less than engineering stress. 2. Not enough. From the definition of toughness , the true strain at fracture or the true fracture stress are also required. 3. Assuming volume constancy, we have or The longitudinal engineering strain is The diametrical engineering strain is The longitudinal true strain is The diametrical true strain is 4. Given : strength coefficient true strain we have the true ultimate tensile strength and the true area at the onset of necking is ± P A --- = ± P A 0 ----- = AA 0 ² 0 ³ Toughness ±´ d 0 ± f ± = l f µ d f 2 ¶· ¸ l 0 µ d 0 2 ¸ = l f l 0 d 0 d f ---- ¹º »¼ 2 20 1.5 ------ 2 178 == = e l l f l 0 l 0 ------------ l f l 0 1 178 1 –1 7 7 === = e d d f d 0 d 0 --------------- d f d 0 1 1.5 20 1 0.925 ´ l l f l 0 ln 177 ln 5.18 = ´ d
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This note was uploaded on 10/13/2008 for the course ME 324 taught by Professor Boylan during the Spring '08 term at Iowa State.

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chandra_324_hw1_soln - ME324 Sec. D - Solution for HW 1 1....

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