HOMEWORK8KEY

# HOMEWORK8KEY - 3 = 5.9 x10-13(0.89 2 x = 4.9 x10-5 Verify...

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Written Homework Problems: Oxtoby Chapter 14 – 14.11, 14.26, 14.34, 14.40, 14.54, 14.56 14.11 See the student solutions manual. 14.26 The vapor density stays constant at 2.919 g/L in a reaction between only gases. This includes the beginning when there is only NOBr. This means the initially the vapor density of NOBr is 2.919 g/L. From this we can find the initial partial pressure of NOBr: m_NOBr / V = n_NOBr*M_NOBr/V = 2.919 g/L n_NOBr / V = (2.919 g/L)/M_NOBr = 2.919 g/L / 109.91 g/mol P_NOBr = n_NOBr / V *RT = (2.919 g/L / 109.91 g/mol)*0.08206 L.atm/mol/K * 350K = .5798 atm Set up the ice table now: NOBr <=> NO + ½ Br2 I (atm) .5798 0 0 Eq(atm) .5798-x x x/2 We know at equilibrium, p_NOBr + p_NO + p_Br2 = p_NOBr = .675 atm So x = .1904, and p_NOBr, p_NO and p_Br 2 = .389 atm, .190 atm and .0952 atm b) K = (p_Br 2 ) 1/2 p_NO / p_NOBR = .150 14.34 2 NO 2 (g) <=> 2 NO(g) + O 2 (g) I(atm) 0.89 0 0 Eq(atm) 0.89-2x 2x x x(2x) 2 /(0.89-2x) 2 = 5.9 x10 -13

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K is small compared to 0.89, so 0.89-2x is about 0.89. 4x
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Unformatted text preview: 3 = 5.9 x10-13 (0.89) 2 x = 4.9 x10-5 Verify x/0.89 = 4.9E-5/0.89 is less than 1x10-4 so it is valid to ignore 2x. At equilibrium: p_NO 2 = 0.89 atm p_NO = 9.8 x10-5 atm p_O 2 = 4.9 x10-5 atm 14.40 Both gases come from ammonium carbamate. So at equilibrium, p_NH 3 = 2p_CO 2 . Also, p_NH 3 + p_CO 2 = 0.115 atm. So 2p_CO 2 + p_CO 2 = 0.115 atm At equilibrium: p_CO 2 = 0.0383 atm and p_NH 3 = 2p_CO 2 = 0.0767 atm b) Use equilibrium partial pressures: K = (p_NH 3 ) 2 p_CO 2 = (0.0767) 2 (0.0383) = 2.25x10-4 14.54 a) Left. b) Left c) Left. d) Pumping an inert gas at constant T and P increases V. Increasing V shifts equilibrium to right. e) Partial pressures of reactive gases stay constant. They are still at equilibrium. So equilibrium does not shift. 14.56 a) K increases with T means delta H is positive => endothermic reaction b) This means reactants give more gas molecules than products. This is a net decrease in the number of gas molecules when we convert reactants to products....
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HOMEWORK8KEY - 3 = 5.9 x10-13(0.89 2 x = 4.9 x10-5 Verify...

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