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Unformatted text preview: 6-35. The wave function is given by: x Cexpmx22h. (a) Normalization: x 2dxC2expmx2hdx12C2expmx2hdx12C22hm1Cmh1/4(b) x2*x x2x dxmh1/22x2expmx2hdx2mh1/24hm3/2h2m(c) V*x 12m2x2x dx12m2*x x2x dx12m2x2h46-38. We know thatEnn12hand En1n32h. Hence, EnEnhn12h1n12.In the limit of large n, EnEn, as expected from the correspondence principle. 6-41. (a) For x< 0, x Aexpik1xBexpik1x,k12mEh24mVh2. For x> 0, x Cexpik2x,k22m EVh22mVh2k12. (b) Use continuity of wave function at x= 0: ABC-- (1) Use continuity of derivative of wave function at x= 0: k1ABk2C-- (2) Solve the two simultaneous equations: Bk2k1k1k2A121...
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- Spring '08