EEE460_Hmwk05_Solution - EEE 460 Nuclear Concepts for the...

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Unformatted text preview: EEE 460 Nuclear Concepts for the 21st Century Spring 2006 Problem: This problem uses data from the U.S. National Institute of Standards and Technology (NIST), see . Using photon energies from 1 keV to 20 MeV: (a) on the same log-log graph, plot the mass attenuation (μ/ρ) and energy-absorption (μen/ρ) coefficients for lead, and (b) on a second log-log graph, plot the half-thickness (in mm) of both lead and ordinary concrete. [16 points] Solution: (a) For lead (Pb), the coefficients are Lead (Pb) 10000 Mass Coefficients (cm²/g) 1000 100 10 1 0.1 0.01 0.001 Attenuation (µ/ρ) Energy Absorption (µen/ρ) 0.01 0.1 1 10 100 Photon Energy (MeV) (b) The half-thickness for Pb and concrete are 1000 100 10 1 0.1 0.01 0.001 0.0001 0.001 Ordinary Concrete Lead Half-Thickness (mm) 0.01 0.1 1 10 100 Photon Energy (MeV) EEE460-Homework K.E. Holbert ...
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This note was uploaded on 10/15/2008 for the course EEE 460 taught by Professor Holbert during the Spring '06 term at ASU.

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