Exam 1 F08Key

Exam 1 F08Key - Name_ 1 Cell Biology Exam 1 October 3, 2008...

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Cell Biology Exam 1 October 3, 2008 Please read each question carefully. Multiple choice questions are worth four points and should be answered on the IF-AT form. A correct answer on the first try receives full credit. A correct answer on the second try receives two points. A correct answer on the third try receives one point. Mark the IF-AT forms carefully, and make no extraneous scratches. A scratch on an extra box will be considered an incorrect answer even if the box is not fully revealed. Be careful that the number of the question that you scratch on the IF-AT form is the same as the number on the exam. 1. Which of the following is a correct description of the function of the rough endoplasmic reticulum? A. Lipid synthesis and detoxification B. Modification of secretory and integral membrane proteins C. Synthesis of cytoplasmic proteins D. Synthesis of secretory and integral membrane proteins E. Used to transport proteins and lipids within the cell. 2. Draw the structure of your favorite amino acid indicating the positions of all the atoms (no shorthand or shortcuts). Circle or somehow clearly highlight the side chain. (4 pts) Virtually no one lost points here. Bravo. 3. You need to make 0.5 mL of a 100 μ M p-nitrophenol standard solution from a 2 mM stock solution of p-nitrophenol. How would you make the 100 μ M p-nitrophenol standard? (0.02 M NaOH will be used to dilute the stock) Please show your work, and remember your units . (4 pts) C1 = 2 mM V2 = 0.5 mL C2 = 100 μ M = 100 μ M(1 mM/1000 μ M) = 0.1 mM (2 mM)V2 = (0.5 mL) (0.1 mM) V2 = (0.5 mL) (0.1 mM ) 2 mM V2 = 0.025 ml Volume of diluent = V2 – V1 = 0.5 ml – 0.025 ml = 0.475 ml Volume of 2 mM stock needed: ____ 0.025 ml _____ Volume of 0.02 M NaOH needed: _ 0.475 ml ___ 1 Name_____________________________ A few people were thrown off by the 0.02 M NaOH. The composition of the liquid that you are using to dilute (the diluent) does not factor into concentration calculation. Only the diluent’s volume matters. Unless, the diluent also contains some of the solute you are trying to calc for = p-nitrophenol in this example.
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For questions 4-8. The four polo-like kinase proteins (PLK1 – 4) comprise a family of enzymes that phosphorylate either a serine or threonine residue on the substrate protein that they recognize. PLKs are known to phosphorylate a number of proteins that promote cell division. Interestingly, levels of PLK-1 are elevated in many types of human cancers. Therefore, there is great interest in understanding the structure and function of all the PLKs. 5. Name the level of protein structure that these coiled structures represent, name the bonds that hold this structure together, AND describe where the bonds form. (4 pts) Structure Level: secondary structure Type of Bonds Involved: hydrogen bonds Location of Bonding: along the backbone or mainchain 6. All of the polo-like kinase proteins contain two distinct domains: an ATP-binding/catalysis domain and a polo-like box domain that mediates the binding of a particular polo-like kinase protein to its
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This note was uploaded on 10/16/2008 for the course BIO 315 taught by Professor Howard during the Fall '08 term at Wisc La Crosse.

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Exam 1 F08Key - Name_ 1 Cell Biology Exam 1 October 3, 2008...

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