(FCY_1) BME140 Fall 08 HW#3 solutions

(FCY_1) BME140 Fall 08 HW#3 solutions - Bt-“ME {40—...

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Unformatted text preview: Bt-“ME {40— b” 2008 G) HEM Fr ’5’ -- :0 JAM I, ééua-{m gal/we: s: 71; l-lfufgf vfibflé “NIH gal/Va 1? @9741; L) m of ear/L1 cfiflér ( .? 54M“ .L: fro/gm) r"; a; ( “A: lg 50]? ) - (Val; £1 C AIS-74m 9A mf/ [Gégrwl’e unryél MAI/>1 fv/flli’fi'hf' in" i‘é’sfiwg Ila/Mew‘cg/ Mafia); /9.915,.7éj 14/50 #0719 % 61ml; u; arc/‘mvé ((441. amt MI 33 54m!“ to} — Anew/L I'li r‘c’stga “‘19 5-“ Qflét‘"k9[c; f‘é’er‘wj %6 $015 $14- 0 74 Aflff’c £01,099 ‘ 9 5"»!00 - gcrouo C23 “£313”qu Jukjyfi L I a???“ a[' But: of 3 475548 regain; ‘9 m; (D m‘ 200 ~: No Q ,005’ x '2. 00 4- -%'(,505’5339 :/_75.. (3) , 045"} 5120 :_ 22.5, C2) .WISX 200 .EI—(agéxgoa :2“! C2) The hand poaition data first needs to be differentiated to get velocity information: dx(t)/dt = 20*cos(10*t) dy(t)i’dt = 5*sin(5*t)- At this point, one should generate a digitized version of data in either excel or matlab. For each time point, the velocity signal should be normalized to get the directional component of the velocity (unit magnitude). Let’s define the hand directional components as NV3t and N V). for the x and 3/ components, respectively. Thefiring rates can be calculated 'by adding the average firing rate to the dot product between the preferred directions and the nonnalized firing rates. D10) = 3 + 0.707*vi(t)_+ 0303*va(9 - v - D20) = 3 — 0.5% N'me + 0.866*NVy(t) Plotting yields: 3.3 1:. neuron 1 .- neuron 2 3.6 3.4 3.2 Discharge rate (Hz) IL.) 2 ' ' '1‘ —'—‘ "l— ‘l— "—J 0 0.2 0.4 0.6 {1.3 1 1.2 1.4 TIITIE (s eeonds) 4 b) A; J‘U: H I; a“ [fling Jéfiwhv “Galwa if I //gwce {a cl r 14/ ew’nfil- 61mm; 1/; Jars JMMAL; mf mm may”,qu ,r X: 06:04 #5417 a *L’ “I, ‘ yW" "Formal; {é I'M/fl Jame fly? : w «w . (Fig; flfl'fl 5'92 g/Wafi) Anya (if? a: ' 4?: gag $8542“?! a; Mantra/2mg —A {$8 MaXrltva, Mngéa 74 Va , dirk/3’9; I mug-M “P W Jam 1% //u ML: 91/67,; A“ d Wu‘rmnr/fi’gp “4/” if “a. Qwa SV‘L Avwéu r? J (.119 Max:454 :96 If [0 W g5”) [:45 Vp/wz to I 9.3. AA #390 .—m "1'83 —?a 0 9-: (W 270 360 G) ‘mi 04M", 4” (am A KEV/91859,“ a}; . “F: M M" Avg??? I'eéfrhn/z/ 5/5252 74 f? 5657-94 , (I? p20; [Uh/g7 Jinan“. I.) Ef’floflMC-fi fit? "EXfiVM/JA .-P 1/414} :7; vas‘mw lxfiécf-Q/r/ {.5 5 a "D Z : 1/ 9%: Maine 4‘M7y'waxfffi) (a) EV it- ?"963' fiyjflrfl I 13,; 34,3 fl?" 1-; A.” fut—f (Abe. Dill/11¢! A63 oVZ/ Lfi’pk-r'C/r-W Mu!va //,{M a?! 55 wfllcu‘; 0/ / m»; 53;;- _ ‘5) fl”? $1.;th ITS, a}; avg/fig; _ €33“, 76ft: 54¢ Z 77%{ M? (0“) We Z 9‘1"”: ‘Mm/ i? Q” = 6w 2;) (m Pow H Arm __ 0’41— : 3.; Err.“ H Am»? 0 (L [w ail/angriqude “$0 {3' Hugo 5’! 9% I’vfflfiéflwi) :zéjév/ r: _# EM, (R- 2T7“ ...
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(FCY_1) BME140 Fall 08 HW#3 solutions - Bt-“ME {40—...

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