ClassNotes5_28_08

# ClassNotes5_28_08 - THE REJECTION REGION METHOD Page 346...

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Unformatted text preview: THE REJECTION REGION METHOD Page 346 11.37 n=20 σ=50 α=.05 X=569 1. Ho: μ = 560 Ha: μ > 560 2. α=.05 3 If the results you get were: what would you do?-10 --shouldn't come into play because you shouldn’t set it up so it would be this wa 0.1 --Do not reject Ho 10 --Reject Ho 4. Reject Ho if Z > 1.645 0.45 α=0.05 Z α/2 Didn't divide alpha by 2, This is a ONE sided test. Get the Z from the tables 5. Since Z is NOT greater than 1.645, we do NOT reject Ho. See, does not fall in the rejection region, so w 0.8 Z α Problem 11.39 n=50 σ=6 α=.05 X=(after-before)/before= n X Z σ μ- = 80 . 20 50 560 569 =- = 1. Ho: μ =0 Ha: μ < 0 2. α=.05 3 4. Reject Ho if Z < 1.645 α=0.05 0.45 z-Z α=-1.45 5. Since Z is not less than 1.645, we cannot reject Ho Problem 11.35 n=100 σ=400 α=.05 X=(after-before)/before=5065 1. Ho: μ =5000 Ha: μ > 5000 2. α=.05 3 1.63 4. Reject Ho if Z > 1.645 α=0.05 z z=1.625 Z α=645 5. Since Z is not greater than 1.645, we cannot reject Ho n X Z σ μ- = 41 . 1 50 6 2 . 1- =-- = n X Z σ μ- = =- = 100 400 5000 5065 Problem 11.33 n=10 σ=0.05 α=.05 X=.493 1. Ho: μ =0.5 Ha: μ ≠.05 2. α=.05 3 4. Reject Ho if Z >Zα = 1.96-or- Z <-Zα =-1.96 0.48 α=0.025 α=0.025 0.48 z Z α/2=1.96-0.44 Z α/2=1.96 5. Since Z-.44 and this is not less than -Za/2, we cannot reject Ho The P-Value method The probability of obtaining A test statistic (Z) as extreme or more extreme than that actually obtained...
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ClassNotes5_28_08 - THE REJECTION REGION METHOD Page 346...

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