{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

solution_pdf2

solution_pdf2 - chaney(glc568 Motion in one dimension...

This preview shows pages 1–3. Sign up to view the full content.

chaney (glc568) – Motion in one dimension – murthy – (21118) 1 This print-out should have 36 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 2) 10.0 points While John is traveling along an interstate highway, he notices a(n) 147 mi marker as he passes through town. Later John passes a(n) 112 mi marker. a) What is the distance between town and John’s current location? Correct answer: 35 mi. Explanation: The change in position is given by Δ s = s f - s o so that the distance between the points is d = | b - a | = | 112 mi - 147 mi | = 35 mi 002 (part 2 of 2) 10.0 points b) What is John’s current position? Correct answer: 112 mi. Explanation: Position is measured from the original po- sition, so his current position is 112 mi. 003 10.0 points You watch a distant lady driving nails into her front porch at a regular rate of 2 strokes per second. You hear the sound of the blows exactly synchronized with the blows you see. And then you hear one more blow after you see her stop hammering. How far away is she? The speed of sound is 340 m / s. 1. 680 m. 2. 1360 m. 3. 85 m. 4. 170 m. correct 5. 270 m. Explanation: The clue is the single blow you hear after you see her stop hammering. That blow origi- nated with the next-to-last blow you saw. The very first blow would have appeared as silent, and succeeding blows synchronous with suc- cessive strikes. With 2 strokes per second, the time between strokes is 0 . 5 s: d = vt = (340 m / s) (0 . 5 s) = 170 m . 004 (part 1 of 2) 10.0 points A cyclist maintains a constant velocity of 5 . 7 m / s headed away from point A . At some initial time, the cyclist is 244 m from point A . What will be his displacement from his starting position after 74 s? Correct answer: 421 . 8 m. Explanation: The distance traveled during the t seconds is Δ d = vt = (5 . 7 m / s) (74 s) = 421 . 8 m . 005 (part 2 of 2) 10.0 points What will be his position from point A after that time? Correct answer: 665 . 8 m. Explanation: The position is d = d 0 + Δ d = (244 m) + (421 . 8 m) = 665 . 8 m . 006 (part 1 of 2) 10.0 points Consider a moving object whose position x is plotted as a function of the time t on the following figure:

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
chaney (glc568) – Motion in one dimension – murthy – (21118) 2 2 4 6 2 4 6 t x I II III Clearly, the object moved in different ways during the time intervals denoted I, II and III on the figure. During these three intervals, when was the object’s speed highest? Caution: Do not con- fuse the speed with the velocity. 1. Same speed during each of the three in- tervals. 2. During interval I. 3. During intervals II and III (same speed during those two intervals). 4. During interval II. 5. During interval III. correct Explanation: The velocity v is the slope of the x ( t ) curve; the magnitude v = | v | of this slope is the speed. Looking at the picture we see that the curve is steepest (in absolute magnitude) during the interval III and that is when the object had the highest speed.
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}