chaney (glc568) – Motion in one dimension – murthy – (21118)
1
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have
36
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001
(part 1 of 2) 10.0 points
While John is traveling along an interstate
highway, he notices a(n) 147 mi marker as he
passes through town. Later John passes a(n)
112 mi marker.
a) What is the distance between town and
John’s current location?
Correct answer: 35 mi.
Explanation:
The change in position is given by
Δ
s
=
s
f

s
o
so that the distance between the points is
d
=

b

a

=

112 mi

147 mi

= 35 mi
002
(part 2 of 2) 10.0 points
b) What is John’s current position?
Correct answer: 112 mi.
Explanation:
Position is measured from the original po
sition, so his current position is 112 mi.
003
10.0 points
You watch a distant lady driving nails
into her front porch at a regular rate of 2
strokes per second. You hear the sound of the
blows exactly synchronized with the blows
you see.
And then you hear one more blow
after you see her stop hammering.
How far away is she? The speed of sound is
340 m
/
s.
1.
680 m.
2.
1360 m.
3.
85 m.
4.
170 m.
correct
5.
270 m.
Explanation:
The clue is the single blow you hear after
you see her stop hammering. That blow origi
nated with the nexttolast blow you saw. The
very first blow would have appeared as silent,
and succeeding blows synchronous with suc
cessive strikes. With 2 strokes per second, the
time between strokes is 0
.
5 s:
d
=
vt
= (340 m
/
s) (0
.
5 s) =
170 m
.
004
(part 1 of 2) 10.0 points
A cyclist maintains a constant velocity of
5
.
7 m
/
s headed away from point
A
. At some
initial time, the cyclist is 244 m from point
A
.
What will be his displacement from his
starting position after 74 s?
Correct answer: 421
.
8 m.
Explanation:
The distance traveled during the
t
seconds
is
Δ
d
=
vt
= (5
.
7 m
/
s) (74 s)
=
421
.
8 m
.
005
(part 2 of 2) 10.0 points
What will be his position from point
A
after
that time?
Correct answer: 665
.
8 m.
Explanation:
The position is
d
=
d
0
+ Δ
d
= (244 m) + (421
.
8 m)
=
665
.
8 m
.
006
(part 1 of 2) 10.0 points
Consider a moving object whose position
x
is plotted as a function of the time
t
on the
following figure:
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chaney (glc568) – Motion in one dimension – murthy – (21118)
2
2
4
6
2
4
6
t
x
I
II
III
Clearly, the object moved in different ways
during the time intervals denoted I, II and III
on the figure.
During these three intervals, when was the
object’s
speed
highest? Caution: Do not con
fuse the speed with the velocity.
1.
Same speed during each of the three in
tervals.
2.
During interval I.
3.
During intervals II and III (same speed
during those two intervals).
4.
During interval II.
5.
During interval III.
correct
Explanation:
The velocity
v
is the slope of the
x
(
t
) curve;
the magnitude
v
=

v

of this slope is the
speed.
Looking at the picture we see that
the curve is steepest (in absolute magnitude)
during the interval III and that is when the
object had the highest speed.
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 Spring '08
 MURTHY
 Acceleration, Velocity, Correct Answer, Orders of magnitude, Chaney

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