seunsom (avs294) – HW6 – bohm – (59970)
1
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printout
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have
9
questions.
Multiplechoice questions may continue on
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before answering.
001
(part 1 of 3) 10.0 points
A 13647 N car traveling at 56.9 km/h rounds
a curve of radius 1
.
24
×
10
2
m.
The acceleration of gravity is 9
.
81 m
/
s
2
.
a) Find the centripetal acceleration of the
car.
Correct answer: 2
.
01464 m
/
s
2
.
Explanation:
Basic Concept:
a
c
=
v
t
2
r
Given:
r
= 1
.
24
×
10
2
m
v
t
= 56
.
9 km
/
h
Solution:
a
c
=
(56
.
9 km
/
h)
2
1
.
24
×
10
2
m
·
parenleftbigg
1000 m
1 km
parenrightbigg
2
·
parenleftbigg
1 h
3600 s
parenrightbigg
2
= 2
.
01464 m
/
s
2
002
(part 2 of 3) 10.0 points
b) Find the force that maintains circular mo
tion.
Correct answer: 2802
.
63 N.
Explanation:
Basic Concepts:
F
c
=
ma
c
F
g
=
mg
Given:
F
g
= 13647 N
g
= 9
.
81 m
/
s
2
Solution:
F
c
=
parenleftbigg
F
g
g
parenrightbigg
a
c
=
parenleftbigg
13647 N
9
.
81 m
/
s
2
parenrightbigg
(2
.
01464 m
/
s
2
)
= 2802
.
63 N
003
(part 3 of 3) 10.0 points
c) Find the minimum coefficient of static fric
tion between the tires and the road that will
allow the car to round the curve safely.
Correct answer: 0
.
205366.
Explanation:
Basic Concept:
F
c
=
F
s
=
μ
s
F
n
=
μ
s
F
g
Solution:
μ
s
=
F
c
F
g
=
2802
.
63 N
13647 N
= 0
.
205366
004
10.0 points
A(n) 0
.
42 kg object is swung in a vertical
circular path on a string 0
.
76 m long.
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 Spring '08
 Kaplunovsky
 Force, General Relativity, Correct Answer, Standard gravity

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