Soln3.11 - Solution 3.11 Given w = 0.10 = 18.5 kN m 3 Gs = 2.7 emax = 0.87(loose state emin = 0.51(dense state(a Dr = Relative Density(Dr e max e x

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Solution 3.11 Given: w = 0.10, γ = 18.5 kN/ 3 m , G s = 2.7, e max = 0.87 (loose state), e min = 0.51 (dense state) (a) Relative Density (D r ) D r = min max max e e e e - - x 100 Determine e by first calculating d γ 3 d 18.5 16.8 kN / m 1 w 1.1 γ γ = = = + s w s w
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 10/23/2008 for the course CIVE 310 taught by Professor Iforget during the Fall '08 term at Drexel.

Ask a homework question - tutors are online