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# hw1_answers - Instructor Prof Doyoon Kim TA Diogo Bessam...

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Unformatted text preview: Instructor: Prof. Doyoon Kim TA: Diogo Bessam Please, during (and only during) Fall 2008, report any typo/error you may nd directly to Diogo Bessam ([email protected]) 1.1.36 1.1.64 HW1 answers, math118, 2008, Version2 f (g(x)) = 2+x 4-x ; g(f (x)) = 4x-1 2x+1 ;x=1 (a) C(q(t)) = 625t2 + 25t + 900 (b) for t = 3, C(q(3)) = 6, 600 (c) t = 4 hours (disregard negative solution) x-intercept is x=1/2; y -intercept is f (0) = -1. 1.2.16 1.2.32 1.3.10 1.3.32 1.3.36 see solutions for graded HW y = -6/5x - 3 y = -1/3x + 5/3 (slope-intercept ) or y - 3 = -1/3(x + 2) (point-slope ) y = -6/5x - 3 (a) C(x) = .55x+35, where x denotes number of miles, C(x) the corresponding cost (b) C(50) = 62.5 (c) x = 67.3 miles 1.4.12 r (a) V = 2 (S - 2r2 ) (b) S = 2V + 2r2 r 1.4.18 R(q) = kq(n - q), where q is the number of people who have the disease, n is the number of total population, n - q the number of people who don't have the disease, k is the constant of proportionality 1.4.26 (a) \$1, 100 \$1, 175; \$25, 100 \$29, 375 and \$100, 000 \$113, 750 (b) P (x) = 1.175x, x 50000 1.1x + 3750, x > 50000 1.4.50 1.5.24 1.5.32 1.5.38 1.5.54 If less than 50 checks are are written the second bank oers the better deal. 3 check solutions for graded HW limx+ f (x) = 2; limx- f (x) = -3 5; tells us that as more trials are conducted, the rat's traversal time will approach a minimum time of 5 minutes 1.6.4 does not exist 1.6.12 1.6.26 1.6.40 1.6.44 2.1.16 2.1.28 1/3 (ATTENTION: there was a typo here) f is continuous at x = -1 f is continuous in all real numbers 3/8 meters y = -48x + 36 (slope-intercept ) or y - 12 = -48(x - 1/2) (point-slope ) (a) 2/3 (b) 1/2; depending on precision wanted, the average rate 0.67 might be a good approximation to the instantaneous rate of change 0.5 End. ...
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