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Unformatted text preview: HW3 answers, math118, 2008 Instructor: Prof. Doyoon Kim TA: Diogo Bessam Please, during (and only during) Fall 2008, report any typo/error you may nd di rectly to Diogo Bessam ([email protected]) 2.5.22 (a) P ( t ) = 3 t 2 + 18 t + 48 (b) R ( t ) = 6 t + 18 (c) R (3) = 0 so Δ R = 0(1 / 12) = 0 3.1.4 derivative is negative in x < 1 , 3 < x < 5 , positive in 1 < x < 3 , x > 5 3.1.8 A 3.1.34 g ( x ) = x ( x 2) ( x 1) 2 ; C.N.: x = 0 , x = 2 (also consider x = 1 , asymptote); g is increasing in x < , x > 2 , g is decreasing in < x < 1 , 1 < x < 2 ; C.P.: (0 , 0) , rel. minimum, (2 , 4) rel. maximum 3.1.46 f ( x ) = x (2 x ) x 2 + x +1 ; C.N.: x = 0 , rel. minimum; x = 2 rel. maximum 3.1.50 minimal requirements are: positive x < , < x < 4 null at and 4 , negative x > 4 3.1.68 has to be decreasing in x < , x > 2 and increasing in < x < 1 , 1 < x < 2 , has to have a rel. minimum at x = 0 and a rel. maximum at x = 2 , as the previous points, x = 1 is just another at point but not an extreme...
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 Fall '07
 Vorel
 Math, Calculus, Diogo Bessam, Doyoon Kim TA, rel. minimum

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