homework2 - Prob. 23:10. Solve Prob. 2.9-9 using the...

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Unformatted text preview: Prob. 23:10. Solve Prob. 2.9-9 using the following data: P=10001b, b=3.5in., «#5? Sow-Hon '- Efigt +09 secfion Tn"- ZZfl puff} Im=mflnfi Eth‘m'UM'v 3; m =0'- N + PCOS L66”) *0 N5 ‘- P (58’) *f racism V - Psin (58’) =0 "I =?sin £58“) W’- W i = 1116253261) An A "F' “(lam ib) C031. (5%»; {13.5 in)" g “'22 32 pr? m - _V_ ._ Psin (53°) £08 58' Ar. A = U000 lb) Sl'n L58“) cos (33°) ___F___#_______ (.85 fY‘l.)1 = 36.65 Fri Prob. 2.7-4. A contractor, who finds it necessary to splice Split” PM“ together two 2 x 4 boards (see Appendix D3) to form a long tension member. does so by using four l-in.-diameter bolts to attach two steel splice plates. as shown in Flg. P2.7-4. If the average direct shear stress experienced by each bolt is 2.5 1:51, what is the value of the tensile load Foam-led by the spliced 2 X 4‘5? P2 .74 and P236 fife/effort- flgfr/m ('0 6 1/040/ [Zur‘fligfxéem 6% 5063/61]: 4327-; :o —4T/H9=O fl= 447 fizz/:2“ z .1 a V; 7 ,4; g/z;4,,-)fn-Kz/m)’] “I ,9; 4:; = 0.276/ ér/Qr ,5: 4V » #04474,» 015» ii a a 47/2941»; 9 ’9“: a = I Va“) = /5 6754;; [6.23 = mam- H‘H—H‘HH— cfw . 6’ 7“ = _ i Z; 57' 9156;? :zmM/g 7;; ,m) Zi/th)‘ = “0324:; 7; g Prob. 2.7-9. Two i-in. nylon rods are spliced together by gluing a 2-in. section of plastic pipe over the rod ends. as shown in Fig. P2359. If a tensile force of P -= 350 lb is applied to the spliced nylon rod. what is the average shear stress in the glue joint between the pipe and the rods? [9.7-9 2/9/2 flan .’ fltérmr'nf de/fjf {law 57%;; x): 1/1: (7/pd/I9n3f EZa/X'Znhm of a» c/o/onc fog/J 01cm» flrc'rr .' #1, - 774/4- = if/af/A.)(/rh,)= 177/; {z}: V 9J2: x; 5v“ "797 Mm = ZZZ-5M" 7;? = zzjflr; Prob. 23-12. Shear stress 1- pmduoes a shear strain 15, (between lines in the J: direction and lines in the y direction) of 7,, = 1’ 1200 ,u (i.e., 7 = 0.0012 (:1) Determine the horizontal dis- ’ IE1 placement 6‘ of point A. (b Determine the shear strain y” be- tween the lines in the x' direction and the y' direction. as shown on Fig. P2.7-12. Solufion: 00 hUrI'Zothl Miami- gggmm 0P— goFovmnkhan 120 mm é): J 150 ram J SA: 0,144 mm b)shewr‘ Strain dg'ggmm fimtmm m at- dePo’mah'on x: meta“??? 50.20 m iii SA H ISO mm I’l’rob. 2.8-4. The fetestay (cable) on a sailboat is attached to a tee-bracket on the deck of the boat by a stainless steel pin. If the allowable shear stress in the pin is 75 MPa and the diameter of the pin is 7 mm, what is the allowable tensile force. Tm, in the stay? Cable stay U-brackel f0 {:4 {72% .' _ (I I _——— . __T , fleferm 2'» e 4 //gu/ a J A: (a [/5 Tee-bracket Boat deck frame/J. E gag'gx'éxx'am : Put-4 “Prob. 2.8-1}. Ari angle bracket ABC is restrained by a high- strength steel wire CD, and it supports a load P at A, as shown in Fig. PIS-11. The strength properties of the wire and the shear pin at B are or = 350 MP; (wire). and n, - 300 MPa (pin at B). If the wire and pin are to be sized to provide a factor of safety against yielding of the wire of F3, =- 3.3 and a factor of safety against ultimate shear failure of the pin of P25. = 3.5, what are the required diameters of the wire (to the nearest mm) and the pin (to the nearest mm}? fake/{'90: fidff/‘and 04me 19/ filg («e/1;! finaj a/t'dhn'ff/a [JILL {fa/‘A' 46%”?! 0; 714M 6 J'KZ'ML, =0 . {/émifisar/fi’ )(rdfm J I 7.3000“... ):0 7; ’/.2074£A/ 52%; no =6’AA/Hm'1/r‘) + BK + 7:, =0 6: : -o, 9456 m +11 27-? =0 5} “MM fimlf‘] L0 £53, ’ 0. $6.574” ,3 ZFSO 6—- fi‘nfih Afff‘fé/I/ v .Y . z B/L fl/fim/‘éJ/c — J/L/fj'f o/c’r/‘fin .' M}: %rnrrbn.' (53;; {Agwf 0; )m'w (fl - IV— _ Egg“- (Kw ’ 5} = (4,, {Mini ' Ffr " HF.” i/fl/Ffle' g m4 (MW/Mfr! — 1mm =£§O7mm :3/7/rhm m: Jr’amc [(07 ma';/ 5: fit: narmf mm fate/fr fl“ flare :24 Am. mmfirg at, = 4 m J 49 = 45mm—t ...
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This homework help was uploaded on 04/06/2008 for the course AME 20241 taught by Professor Wagner during the Spring '08 term at Notre Dame.

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homework2 - Prob. 23:10. Solve Prob. 2.9-9 using the...

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