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Unformatted text preview: Prob. 23:10. Solve Prob. 2.99 using the following data: P=10001b, b=3.5in., «#5? SowHon '
Eﬁgt +09 secﬁon Tn" ZZﬂ puff}
Im=mﬂnﬁ Eth‘m'UM'v
3; m =0' N + PCOS L66”) *0
N5 ‘ P (58’) *f racism V  Psin (58’) =0 "I =?sin £58“)
W’
W i = 1116253261)
An A
"F' “(lam ib) C031. (5%»;
{13.5 in)"
g “'22 32 pr?
m  _V_ ._ Psin (53°) £08 58'
Ar. A
= U000 lb) Sl'n L58“) cos (33°)
___F___#_______
(.85 fY‘l.)1
= 36.65 Fri Prob. 2.74. A contractor, who ﬁnds it necessary to splice Split” PM“ together two 2 x 4 boards (see Appendix D3) to form a
long tension member. does so by using four lin.diameter
bolts to attach two steel splice plates. as shown in Flg.
P2.74. If the average direct shear stress experienced by each
bolt is 2.5 1:51, what is the value of the tensile load Foamled
by the spliced 2 X 4‘5? P2 .74 and P236 ﬁfe/effort ﬂgfr/m ('0 6 1/040/ [Zur‘ﬂigfxéem 6% 5063/61]: 4327; :o —4T/H9=O
ﬂ= 447
ﬁzz/:2“
z .1 a V; 7 ,4; g/z;4,,)fnKz/m)’]
“I ,9; 4:;
= 0.276/ ér/Qr ,5: 4V » #04474,» 015» ii a a 47/2941»;
9 ’9“: a = I Va“) = /5 6754;; [6.23 = mam H‘H—H‘HH—
cfw . 6’ 7“ = _ i Z; 57' 9156;? :zmM/g
7;; ,m) Zi/th)‘ = “0324:; 7; g Prob. 2.79. Two iin. nylon rods are spliced together by
gluing a 2in. section of plastic pipe over the rod ends. as
shown in Fig. P2359. If a tensile force of P = 350 lb is applied
to the spliced nylon rod. what is the average shear stress in
the glue joint between the pipe and the rods? [9.79 2/9/2 flan .’ ﬂtérmr'nf de/fjf {law 57%;; x): 1/1: (7/pd/I9n3f EZa/X'Znhm of a» c/o/onc fog/J 01cm» ﬂrc'rr .' #1,  774/4 = if/af/A.)(/rh,)= 177/; {z}: V 9J2: x; 5v“ "797 Mm = ZZZ5M" 7;? = zzjﬂr; Prob. 2312. Shear stress 1 pmduoes a shear strain 15, (between lines in the J: direction and lines in the y direction) of 7,, = 1’
1200 ,u (i.e., 7 = 0.0012 (:1) Determine the horizontal dis ’ IE1
placement 6‘ of point A. (b Determine the shear strain y” be tween the lines in the x' direction and the y' direction. as shown
on Fig. P2.712. Soluﬁon:
00 hUrI'Zothl Miami gggmm 0P— goFovmnkhan 120 mm é): J 150 ram J SA: 0,144 mm b)shewr‘ Strain
dg'ggmm ﬁmtmm m at dePo’mah'on x: meta“??? 50.20 m iii SA
H ISO mm I’l’rob. 2.84. The fetestay (cable) on a sailboat is attached
to a teebracket on the deck of the boat by a stainless steel
pin. If the allowable shear stress in the pin is 75 MPa and
the diameter of the pin is 7 mm, what is the allowable tensile force. Tm, in the stay? Cable stay
Ubrackel
f0 {:4 {72% .' _ (I I
_——— . __T ,
ﬂeferm 2'» e 4 //gu/ a J A: (a [/5 Teebracket
Boat deck frame/J. E gag'gx'éxx'am : Put4 “Prob. 2.81}. Ari angle bracket ABC is restrained by a high
strength steel wire CD, and it supports a load P at A, as
shown in Fig. PIS11. The strength properties of the wire
and the shear pin at B are or = 350 MP; (wire). and n, 
300 MPa (pin at B). If the wire and pin are to be sized to
provide a factor of safety against yielding of the wire of
F3, = 3.3 and a factor of safety against ultimate shear failure
of the pin of P25. = 3.5, what are the required diameters of
the wire (to the nearest mm) and the pin (to the nearest mm}? fake/{'90: ﬁdff/‘and 04me 19/ ﬁlg («e/1;!
ﬁnaj a/t'dhn'ff/a [JILL {fa/‘A' 46%”?! 0; 714M 6 J'KZ'ML, =0
. {/émiﬁsar/ﬁ’ )(rdfm J I 7.3000“... ):0
7; ’/.2074£A/
52%; no
=6’AA/Hm'1/r‘) + BK + 7:, =0
6: : o, 9456 m +11 27? =0
5} “MM ﬁmlf‘] L0 £53, ’ 0. $6.574” ,3 ZFSO
6— ﬁ‘nﬁh Afff‘fé/I/ v .Y . z B/L
ﬂ/ﬁm/‘éJ/c — J/L/fj'f o/c’r/‘ﬁn .'
M}: %rnrrbn.' (53;; {Agwf
0; )m'w (ﬂ  IV— _ Egg“
(Kw ’ 5} = (4,, {Mini ' Ffr " HF.”
i/ﬂ/Fﬂe' g m4
(MW/Mfr! — 1mm =£§O7mm :3/7/rhm m: Jr’amc [(07 ma';/ 5: ﬁt: narmf mm fate/fr ﬂ“
ﬂare :24 Am. mmﬁrg at, = 4 m J 49 = 45mm—t ...
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 Spring '08
 Wagner
 Shear Stress, Tensile strength, Shear strength, Psin, direct shear stress

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