Physics Test 3 2000

# Physics Test 3 2000 - 2 overnheﬂﬂﬂﬂ Physics llEih...

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Unformatted text preview: 2. overnheﬂﬂﬂﬂ Physics llEih Third Partial Examination lee 3 ......... .,_ I.D.#: Sign at a re: Please circle your section: Section 1 2 3 4 Ins r i ions This is a one honr+. eioeed hook examination. Pet answers in the boxes provided, or oiroie the heat answer. If numerical answers are needed, you must include units. Any woric needed to justify the answer must be shown in the space provided. A correct answer without the necesser justifying worit may not receive any credit. You iriaj.r use the formula. sheet at the has}: of the exam. Total point scores for each problem will appear in the table below and in { } beside each problem number. Do what is easiest ﬁrst. AVOID giantess; at anyone else's paper during the examl The Honor Code is in effect. Please sign the exam to indicate your Honor Pledge. Good inch! Point Tallies for the Exam Problems 1 5*? I 'II-i'. E E 1] Shurt Quarrimrs (Shuwing work can get :rﬂu partial credit] Ii E (Circle the Correct Respanae}: ill- a] Haw much energy is 5:0er in a, mlermirl {if lerrgrh 113 cm. area, 5.13 cm2 and 1m} turna of wire if it carries 12.0 mnps'.’ {3 puts] ﬁt _ I""—*—~—._..__‘ .3 Cumulmﬁrj U1: 13* L "L 11} T54 micro-Jaulm .., = A my "321:: micm—Jﬂuies _ I : Em" A)? ~ £4 c» N I“ IV} 5.23 micro-Joules ‘F" f r *5} ' 1- 5 le k! 1'“ L I.- H I' . u-I-I" 1r} 213 nanU-Jrsules _ {afﬁx {5 ﬂ khﬂhk] m rm (.lh IQ=LEKEG'§H . 2. UL: iLlemKSH-r) 01-07233 _3 3%.‘5LKW j b} in 3.9 secands the curmnt in a, particular RL circuit that runsista of a battery, a msistﬂr, and an indisctnr cemented in series, has increased to as mine that is 513% 132' the rrsaximum current passibie. If the resistor has a mm of 3.99 Uhrns. what '.th':it frh'd-rTﬁt: , ~ r; e m 11:: anceu I: :11 UL or I: p a.) {ma F}! umﬂgﬁh—ﬁ n was: Harri-ya " r. i: {"12 II] 1.4 Henry's ~ S g 177/0 -‘ E III} 2.1] Henry's ' f __ 3/5; 1 ‘b 1' E 4. _ _ , V) 13 Henrya .ll h E c} A Easer berm] passer; {mm air in glass. What happenﬁ m the wavelength uf this 1ight?{2 pus} w , “>5 E H l 32. L}...I_rrr§r&rs.. I 3’ NH I—IM%—:: L ': fﬂlm EH} Stays rhﬂ same 1) Shert Questions {continued} d} In which direction is this Electric Ficiri painting fer this traveilitig eiecremsg— netie w:we'?{2 put] a: J .3 S L“ S 1} Up {Ma ii] Dawn __ B tﬁﬁaﬁﬁeuwu .. 1V Uni cf the Page 5— e} What is the Erititlﬂj magic fer tetei intents} refiecticrli for Eight trsveiing it: the cure {inner part) of he opticai iiiier if the cure has as itldEL'IC sf refractien of n = 1.5 and the cladding {miter mvering] cf the ﬁber has an imiex cf refraction ef 21.3?{2 pts}' "1 I a:- n=l.3 L—i, clad ' ﬂ 3; Z ‘ : ﬂ ‘— mﬁé 11:15 ﬂihhgi ‘1”) L - cladding _, . F_ 1131.3 El": gmgc F L3 3154:3139 . _ iiis=iei EMQCEQ. {thesis} :."5‘ _.._~ 5 a" t r"! 1? ﬂ)” 9; _ Sr“ «:2 rcs‘” 1' i") Pr ﬂying fish, under water (nmiﬁS). sees the sun at an apparent angle sf 45“ fmm the vertical. Fit whet angle frem the vertical cities this ﬁsh see the sun when it “ﬂies” admire {1121119} the water?{3 pts} V1 _,;-_ i I) s = 21]“ EU? = 32“ "M. iii) 3 is” 1,. { 3; J, ivheetesﬂ V V s '= iii“ 2} Induced EMFJE paints {Show year Werk!) In the ﬁgure belew, an external feree ie uteri to more a eenrlueting leep of sides a. and a. reeieterlee H thmugh a magnetic ﬁeitl at n, mneterﬂ; reitlt'ity V the ehewn. This predeeee an induced Emf in the 1009.. and a reeultitsg current. If R = 2.121 R, :1 115 err, 11 a: 143 rrtfe1 and B 2 [LE T {B pGiIIEE illtﬂ the page and is: nonrzere only te ETIE'. left of the dotted line: as on the ﬁgure}: LUTTEM+ ~+ zeraﬂ +3 + i c/ “riﬂe-S;sz 3-”? q—a—l—wrar ' F :3: _’ externalwg ﬁﬂ Bill/1 1 + .1... a} Indicate en the ﬁgure the direction at" the eurrent.{3 pte.} b] What is the value 0f this current? h __ mirage \Dm/g [horse tam} L QrQJL :zO‘S/ﬂK c) TlE't’httt- is the value of the external force? i...- F = E FwIiG> [mtlewe =(FMSMMN) *1 0.5;?) Raft :OﬂSN FP~LR-L u L/ awe: i __ .___. _. 31 Refraction { 15 points) A mirror sits at the bottom of a pool. Light is ineideat on the surfaee of the goo] as shown, stokes the mirror, and is reflected baek towards the surface. What is the minimum angle With which you can tilt the mirror so that none of the light reﬂeeted by the mirror escapes the pool? The index of refraction for water is 1.33 and that for air is 1. {note: Figure is a guide only! Le. you eao't "measure" the answer from the figure!) ---\._._,..__ _____________________ __ {Try to show as much work as you can for partial eredit.) Wpehimi'gc-W 1[@t+@) : [gig-o .- 4) Foiarization (15 points) [Show your work!) initially,r unpolariaed light is incident upon 2 poiarizers. These polariaers have their transmission axes oriented at 90 degrees relative to each other. If the incident light has an intensity,r of 1:151: was? ~ ~ - - (light 13 [Imva m the: ﬁght} What is the intensityr of the transmitted light? 15'; Shea 2nd sheet Transmitted light? Incident ' ﬂu, ﬁght Transmission Transmission axis 1 axi s H 1 Now, a third sheet is inserted between the ist and 2nd sheet at an angle of 10 degrees relatisiejo the first sheet.{1ndicate on the ﬁgure the direction of the transmitted Electric Field, if arlj‘w and Sheet s e we 3'00“) as." in“? Lassa Us? 100 {first}; 1 t-Ljﬁfb ii: i ﬁnd sheet if"? 52+. Wranﬂ'ﬁ What is the intensity of the transmitted light? tst Sheet! Incident be 7’] ii In T ;: I Trans Mir“ 1),. ransrnitted light? ; Transmission Transmission ' asis w axis Transmission .... i It; . -_-- .—-- '2— 6 1-» t2: axis sis? m1.- {ﬁg t0 C05 80 ,3. w w ....... ._......_ .... Equations jag? fzfydﬂi VEIH: F=IH ‘13::rran __ _ ' H @15- fB+ ~53: E = —d:—t31 953 H.331 {.mmetiﬁms], .5 = —LL [Increasing]: I = Igﬂ — {3—HT}, "r 2 LEE {dECTﬁaS'é'ngj I = ﬁgs—UT IE9=ITxfBX df’mrﬁxﬁ, \$3=ff+dﬁ+ d I d 1 (id; gﬁ‘gg = “\$5 =‘ Mﬁﬂ%+ﬂﬂ-{eﬁndﬁsms afﬂispmocmen: = Eﬂ‘mﬁ H = Mn} (gamma; L a» mum (soiermid) U; = {132) L12, Mg «m: (132} CV3. “a a \$2,!me 11:3 3 maﬁa r: = Efﬁ, Pressure = Sic, 3+ = [UH-nu} f >1 3’1 3m; = Emurﬁnmxﬁgﬁﬂ} —r —> . E =Egﬁlﬂ£k\$-Wt}, kmﬂfr/JH‘ w=21rrf, cﬂﬂwm=ifﬂ lfﬁfmu} m 31113; 2 n2 sinﬂg {Enema LawL 511191: a raging, n m cfv, mil 2 712.313 ‘2 _ _ _ Erq-amnisaim; E 2 E5 “3’3 Hmhrizﬂf: 1’ Z" 1'1} C05 HMurizerr ﬁpaﬂmer — HE “gums .. rim” IuﬁFﬂ‘lﬂTi-Iﬂd _} fwﬂﬁzeﬁfﬂy ﬁrmL-ﬁ: ” ' [ii—3’ ﬂ FL PGWEV = — “F” F“ d: Cﬂnsﬁants #9 = 41: x in“? T111 £9 2 3.35 x 113—” 15%;; c = 31:! 3: 1&3 mix y = 9.8 mfs2 ...
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## This note was uploaded on 10/25/2008 for the course PHYS 116b taught by Professor Haglund during the Fall '07 term at Vanderbilt.

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Physics Test 3 2000 - 2 overnheﬂﬂﬂﬂ Physics llEih...

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