# HW4 - *3-56 The ends of the three cables are attached to a...

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Unformatted text preview: *3-56. The ends of the three cables are attached to a ring at A and to the edge of the uniform plate. Determine the largest mass the plate can have if each cable can support a maximum tension of 15 kN. W=Wk 4 6 12 F = —— —— -— W B “(14 141 14 ) 6 4 12 F =F —-—i—— —— c C( 14 14j 14) 4 6 12 F Fv = —_- —— —-k 5 F F” F”( 14.4, 14J 14 ) C 4 6 4 F, = ; —— — ——F --—F = 1: o 14F, 14 c 14 n o 6 4 6 25—0, "ﬁFD—TZFC'l‘TZFD-O _ . _12 .__1_2 _1_2 _ Thus. x11; -0, up, 14175 1417,,+w.0 12 12 AssumeFB-=15kN. Solving. "ﬁus)'°'ﬁ“5’+w=° Fc = o < 15 kN (0K) W: 25.714 kN F =15m (ox) " m=!=-Zi'7—l4=2.62Mg Ans *3—64. The 25-kg ﬂowelpot is supported at A by the three cords. Determine the force acting in each cord [or equilibrium. FAD = FAD (sin30°i —cos 30° sin60°j + cosBO° cos 60°k) F = 0.511;; — 0.75ij + 0.43301fmk “‘7 33’ FAC = PAC (—sin30°i 700530°sin60°j + cos30°coséO°k) K =—0.55Ci—o.75acj+o.433oack 251m FAB = Em (sin45°j +cos45°k) = 0.70711131' + 0.707113“g k F = —25(9.81)k = {—245.25k}N IF = 0; FAD +1?” +FAC +F =0 (0.5FADi — 0751i4 Dj +0.4330E1 D k) + (07071};1 B j + 0.70711?” k) + (—0.5FACi —0.751§‘Cj+ 0.4330ﬂck) + (—245.25k) = 0 (0.5FAD —O.51ic) i + (—0.75F;D + 0.70711?“B —O.75ﬂc) j «043301311, +0.70711r;1 B +0.4330FAC —245.25) k = 0 Thus, 2F; =0; 0559—05ﬁc = [1] XI; = O; —0.75Ew + 0.7071531, — 0.75IQC = 0 [2] £5 = 0; 0.4330130 + 0.7071151“B +0.4330PAC — 245.25 = O [3] Solving Eqs_[1],[2],and [3] yields: ap=5c=1o4N ﬂ3=220N Ans ...
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HW4 - *3-56 The ends of the three cables are attached to a...

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