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Unformatted text preview: 46. Determine the magnitude of the force F that
should be applied at the end of the lever such that this
force creates a clockwise moment of 15 Nm about point
0 when 0 I 30°. (11% =15Nm = Fens 3D°(0.05 + 0.35in60“)  Fsin30°(0.3c0560°) F = TLSN Ans 413. To correct a birth defect, the tibia of the leg is
straightened using three wires that are attached through
holes made in the bone and then to an external brace that
is worn by the patient. Determine the moment of each
wire force about joint B. (Msh = 4 cos 15° (0.8)  48in 15° (0.02) = 3.07 N m) Ans (Mu)2 = 3(055) = 4.40N m) Ans (Ma )3 600530°(0.2) + 6sin30° (0.015) = Low. m ) Ans 4—18. Determine the direction 6' (00 S 0 S 1800) of the
force F = 401b so that it produces (a) the maximum moment about point A and (b) the minimum moment about
pointA. Compute the moment in each case. (a) 14.04”,“ = 40(J32 +25) = 330 lb . n An: «t = ran~l (g) = l4.04° 9 = 90°  [4.040 = 76.0° Ans
(b) {Huron = 0 Ana ‘15 =tan" (E) =14.04" 9 = l80° — 14.04" = 166” Ans 4—31. The worker is using the bar to pull two pipes together
in order to complete the connection. If he applies a horizontal
force of 80 1b to the handle of the lever, determine the
moment of this force about the end A. What would be the
tension Tin the cable needed to cause the opposite moment
about point A? t+MA = 80 (Scos40°) = 306.4178 = 306lbft') Ans
Require 306.4178 = T sin70°(0.5) T = 652 lb Ans ...
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 Fall '08
 Troxel

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