Chemistry Equations - Chapter 1 1 2 3 4 Kelvin from Celsius TK=tC 273.15 Fahrenheit from Celsius tF=95tC 32 Celsius from Fahrenheit tC=59(tF-32

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Chapter 1 1. Kelvin from Celsius: = ° + . TK t C 273 15 2. Fahrenheit from Celsius: ° = ° + t F 95t C 32 3. Celsius from Fahrenheit: ° = ( ° - ) t C 59 t F 32 4. = ( ) ( ) density d mass m volume V 5. Chapter 2 1. Law of Conservation of Mass: The total mass of substances present after a chemical reaction is the same as the total mass of substances before the reaction. 2. Law of Definite Proportions: All samples of a compound have the same composition-the same proportions by mass of the constituent elements. 3. Law of Multiple Proportions: If two elements form more than a single compound, the masses of one element combined with a fixed mass of the second are in the ratio of small whole numbers. 6. Chapter 3 1. = ×( Mass Percent Element number of atoms of element molar ) × % mass of element molar mass of compound 100 2. Chapter 4 1. = ( ) ( molarity M amount of solute in moles volume of solution in ) liters 3. × = × Mi Vi Mf Vf
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 10/26/2008 for the course CHEM 2070 taught by Professor Chirik,p during the Fall '05 term at Cornell University (Engineering School).

Page1 / 3

Chemistry Equations - Chapter 1 1 2 3 4 Kelvin from Celsius TK=tC 273.15 Fahrenheit from Celsius tF=95tC 32 Celsius from Fahrenheit tC=59(tF-32

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online