midterm_ii_key3

midterm_ii_key3 - 1 BIS 101 - 003 MIDTERM II May 12, 2006...

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1 BIS 101 - 003 MIDTERM II May 12, 2006 READ THE FOLLOWING INSTRUCTIONS: Write your name legibly on each page of this exam. All work must be done in ink . Show all your work. This exam is worth 100 points. You have 50 min. to complete the exam. Authorization for public distribution of graded examination I, ____________________________________, ID _________________________ authorize the University to publicly distribute my graded examination for BIS 101-003. Date_______________________________ Signed: _____________________________ Good Luck!
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2 Name:______________________________ P a g e : 3 ________ 4 ________ 5 ________ 6 ________ 7 ________ 8 ________ 9 ________ Total ________ Bonus_________
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3 Name:______________________________ (1) In a species of tropical fish, a colorful variant called montezuma occurs. When two montezuma are crossed, 2/3 progeny are montezuma and 1/3 are the wild type (green). Montezyma is a single gene trait and montezuma fish are never true-breeding. Explain the inheritance pattern seen here and show how your explanation accounts for the phenotypic ratio given above. (8 points) The montezuma gene (M) is dominant over the wild type allele but is a recessive lethal. Parents Mm x Mm Progeny 1 MM (lethal) : 2 Mm (montezuma) : 1 mm Hence the progeny from mentezuma x montezuma crosses are 2 montezuma : 1 wild type and no montezuma pure line can be produced. (2) In a certain population of frogs, 120 were green, 60 were green-brown, and 20 were brown. The allele for green is denoted G G and that for brown is denoted G B . These two alleles show incomplete dominance relative to each other. (a) What are the genotype frequencies? (3 points) G G G G 120/200 = 0.6 G G G B 60/200 = 0.3 G B G B 20/200 = 0.1 (b) What are the allele frequencies? (6 points) G G frequency is 2(G G G G + G G G B )/2N = (240 + 60)/400 = 0.75 G G frequency is 2(G B G B + G G G B )/2N = (40 + 60)/400 = 0.25 (c) What are the expected frequencies of genotypes if the population is at Hardy- Weinberg equilibrium? (3 points) G G G G p 2 = 0.75 2 = 0.5625 G G G B 2pq = 2 x 0.75 x 0.25 = 0.375 G B G B q 2 = 0.25 2 = 0.065
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midterm_ii_key3 - 1 BIS 101 - 003 MIDTERM II May 12, 2006...

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