problemset2solution

# problemset2solution - PAM 2100 Lecture 1 Fall 2008...

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PAM 2100 Lecture 1 Fall 2008 Instructor: Salam Abdus Problem Set #2 Answer key Total Points: 10 Circle all of your final answers. Put your name and your section number at the top. #1) ACT scores are distributed normally with a mean μ = 28 and a standard deviation σ = 4.8. How high must a student score in order to place in the top 20% of students taking the ACT test? Round your final answer to two decimal places. (2 points) We need to find out the value of x such that the are to the right of x is .20, that is, the area to the left of x is (1-.2)=.8. The closest number to 0.80 is .8023 on table A, and the corresponding z is 0.85. Therefore, our unknown x must solve 08 . 32 , 85 . 0 8 . 4 28 = = - x or x So the answer is 32.08. ( 1 point for the correct z and 1 point for the correct value of x) #2) Solve problem 1.126 (page 74) from the textbook. Explicitly give Tonya’s standardized score, rounded to two decimal places. Explicitly give Jermaine’s standardized score, rounded to two decimal places. (1 point) Tonya got 1318 on SAT. The standardized score is 40 . 1 209 1026 1318 = - = Jermaine got 27 on ACT. The standardized score is 29 . 1 8 . 4 8 . 20 27 = - = Assuming that both tests measure the same thing, Tonya got a higher score. ( .5

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## This note was uploaded on 10/27/2008 for the course PAM 2100 taught by Professor Abdus,s. during the Fall '08 term at Cornell.

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problemset2solution - PAM 2100 Lecture 1 Fall 2008...

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