hw1ece342fall2008Solution

# hw1ece342fall2008Solution - Name _Solution_ CM _111_ ECE342...

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Name ____Solution_______ CM __111___ Due date: Monday, 15 Sept. 2008 ECE342 Homework #1 Solution Fall 2008 (Decibel, Power Gain, Signal Source Specification, EMC) 1 Problem 1.4.4 on page 45 of the textbook by Clayton Paul. (Electrical Length) c 2.998 10 8 × s -1 m = 1. A 50 mi length of 60 Hz power transmission line. k 50000 1.609 60 m s c := k 0.016 = 2. a 500-ft AM braodcast antenna broadcasting at 500kHz. k 500 0.0254 12 500 1000 m s c := k 0.254 = 3. A 4.5-ft FM broadcast antenna broadcasting at 110MHz. k 4.5 0.0254 12 m () 110 1000000 1 s c := k 0.503 = 4. A 2-in land on a printed circuit board (assume a velocity of progation of 1.5x10 8 m/s at 2 GHz. k 0.0254 2 m2 10 9 1 s c 1.5 2.9888 := k 0.675 = ECE342 Fall 2008 Homework #1 Solution Page 1 of 4

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2 Problem 1.4.5 on page 45 of the textbook by Clayton Paul. (Electrical Length) c 2.998 10 8 × s -1 m = 1. i(t,z)=I 0 cos(2 π x10 6 t-2.2x10 -2 z), d=3km. ω 2 π 10 6 rad s := β 2.2 10 2 × rad m := distance 3000m := v ω β := λ 2 π β := TD distance v := φ 360 2 π β distance := v 2.856 10 8 × s -1 m 285.599m = TD 1.05 10 5 × s 3.782 10 3 × = distance 4 0.0254 m := 2. i(t,z)=I 0 cos(6 π x10
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## This note was uploaded on 10/26/2008 for the course ECE 342 taught by Professor Song during the Fall '08 term at Rose-Hulman.

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hw1ece342fall2008Solution - Name _Solution_ CM _111_ ECE342...

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