This preview shows pages 1–6. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: ECE 351 Exam 1
Spring 2008 Name 50¢ So\o"hw\ Section 1
CM \12
Scores:
1)
2)
3)
Total I pledge on my honor that I did not copy any of this exam, and that this work is entirely my own. Furthermore, I did not use PSpice during this exam. Page 1 of 9 Problem 1 125 Points): For the circuit above, assume that B = 20, V31; = 0.7 V, VA = 80 V, and Vcc = 15 V.’
a) Find a numerical value for the current source output current, 10m. (\5 9waf 33
b) Find a numerical value for the current source parallel resistance. ( {a 9;“ng Page 2 of 9 Problem 2: (25 Points) VCC
o The PNP current sources in this circuit have the same numerical values as the source in problem 1. If
you couldn’t do Problem 1, assume that the current is 10 uA and the parallel resistance is 1 M0. a) What value of I] is required to bias the ampliﬁer correctly?(53
b) Draw the model with the PNP current sources replaced by their equivalent current source model.@ ) c) Draw the small signal model for the differential ampliﬁer. (S)
d) Find the differential mode gains ADM] and ADMz. (‘0) Q 1‘ 1 11¢ cam LUKLMW'; ‘Zl.‘{MA Page 4 of 9 Page 5 of 9 Problem 3: 550 Points! A new device has recently been discovered called a BJM Device: 95 in; +
V xy % 1A5 \ The equations that govern this device are:
3/ 2 [Q :KVXY
1A 2 0 Where K is a constant equal to 50 “AN 1'5 . Note that ny is the controlling voltage of this device.
This device is used in the ampliﬁer below. Note that I; is a 100 uA current source: vcc=15 q nome(\ooo + m \) (Ade Cor “We “(Fem
100k V0
VDlUwJ
RA
MJ\
10k
+ Vin 01
I2 +
w DC=100U "LE‘0
'0
VEE=15V “is 3~Tamw death, “is SWMMF “(3 “We?” GM 01.0
L 7/ (6m / 9mg“ ‘7’ 99"“ Page60f9
&9§\.v\’( D 1a 9, King“) 3 3’— \‘Wdh \ gr“ \oms 4W: («runv —r
I %L50 MPIQhSBL W1 $\%{\UQ W\O A112 "IL \.sm\l\ :MSM 69 Page 7 of 9 ...
View
Full
Document
This note was uploaded on 11/04/2008 for the course ECE 351 taught by Professor Herniter during the Spring '08 term at RoseHulman.
 Spring '08
 Herniter

Click to edit the document details