ECE 250 Final Exam Fall 2007 - Solution

ECE 250 Final Exam Fall 2007 - Solution - VG := 15 V 62 k...

Info iconThis preview shows pages 1–10. Sign up to view the full content.

View Full Document Right Arrow Icon
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 4
Background image of page 5

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 6
Background image of page 7

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 8
Background image of page 9

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
V G 15 V 62 k Ω 62 k Ω 91 k Ω + := V G 6.078 V = I DSS 2mA := V P 2 V := I D 1mA := V GS 0V := Given I D I DSS 1 V GS V P 2 = V G V GS I D 12 k Ω + = V GS I D Find V GS I D , () := V GS 0.92 = I D 0.583mA = I DSS 20 mA := V P 8 V := I D 1mA := V GS 0V := Given I D I DSS 1 V GS V P
Background image of page 10
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 11/04/2008 for the course ECE 250 taught by Professor Herniter during the Spring '08 term at Rose-Hulman.

Page1 / 10

ECE 250 Final Exam Fall 2007 - Solution - VG := 15 V 62 k...

This preview shows document pages 1 - 10. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online