TUGAS_2.docx - Diketahui Ditanya a Lokasi Tendon Konkordan...

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Diketahui : Ditanya : a) Lokasi Tendon Konkordan b) Distribusi Tegangan Beton di Tengah bentang BC c) Persamaan Parabola untuk BC Jawab : Mencari equivalent load exerted on concrete by tendon - dengan cara analisis sudut bentang AB θ kiri = 800 11000 , Peθ kiri = 4000 800 11000 = 290.9 kN θ kanan = 600 11000 ,Peθ kanan = 4000 600 11000 = 218.2 kN bentang BC persamaan dasar parabola y = A x 2 + Bx + C masukan 3 titik dalam kurva x = 0 , y =− 0.2 x = 11 , y = 0.4 x = 22 , y = 0 diperoleh nilai
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y = 1 242 x 2 + 0.1 x 0.2 θ kiri = dy dx ( x = 0 ) = 1 121 0 + 0.1 = 0.1 Pe θ kiri = 4000 0.1 = 400 kN θ k anan = dy dx ( x = 22 ) = 1 121 22 + 0.1 = 9 110 Pe θ kanan = 4000 9 110 = 327.27 kN sehingga
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