QUIZ 3.docx - SOAL 1 UAS 2014 Ditanya Apakah struktur kuat...

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SOAL 1 UAS 2014 Ditanya : Apakah struktur kuat menahan gaya? Melengkapi Section Properties y cgc = AiYi Ai = 1000 200 1350 + 400 1000 750 + 250 500 125 1000 200 + 400 1000 + 250 500 = 585625000 725000 = 807.76 mm sehingga dapat ditentukan e max = Y bottom cover = 807.76 200 = 607.76 mm I cgc = 1 12 b h 3 + A r 2 ¿ 1 12 1000 200 3 + 1000 200 ( 1350 807.76 ) 2 + 1 12 400 1000 3 + 1000 400 ( 807.76 750 ) 2 + 1 12 500 25
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¿ 152.39 10 11 m m 4 diasumsikan nilai iterasi awal c= 500 mm ITERASI 1 Lalu dicari kekonvergenan sehingga n H=0 Cc = Tp 1 + Tp 2 + Tp 3 + Ts Kabel Prestress 1 ε pe = σ pe Ep = Pe Ap Ep = 1000 10 3 1000 195000 = 5.13 10 3 ε ce = | 1 Ec ( Pe Ac Pe e 2 Ic ) | ¿ | 1 4700 40 ( −( P e 1 + P e 2 + P e 3 ) Ac P e 1 e 1 2 Ic P e 2 e 2 e 1 Ic P e 3 e 3 e 1 Ic ) | ¿ | 1 4700 40 10 3 ( ( 1000 + 500 + 5500 ) 725000 1000 ∗(− 220 ) 2 152.39 10 11 500 0 ∗− 220 152.39 10 11 5500 607.76 ∗− 220 152.39 10 11 ) | ¿ 1.74 10 4 ε pt = d c c 0.003 = 422.24 500 500 0.003 = 4.67 10 4 ε pn = ε pe + ε ce ε pt = 5.13 10 3 + 1.74 10 4 4.67 10 4 = 4.84 10 3 tanda ε pt negatif karena tendon mengalami tekan f pn = E p ε p { A + 1 A [ 1 + ( B ε p ) c ] 1 c } dengan A=0.0332 , B = 114 , C = 12
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f pn = 195000 4.84 10 3 { 0.0332 + 1 0.0332 [ 1 + ( 114 4.84 10 3 ) 12 ] 1 12 } = 943.15 MPa T p 1 = 943.15 1000 = 943155 N Kabel Prestress 2 ε pe = σ pe Ep = Pe Ap Ep = 500 10 3 500 195000 = 5.13 10 3 ε ce = | 1 Ec ( Pe Ac Pe e 2 Ic ) | ¿ | 1 4700 40 ( −( P e 1 + P e 2 + P e 3 ) Ac P e 1 e 1 2 Ic P e 2 e 2 e 1 Ic P e 3 e 3 e 1 Ic ) | ¿ | 1 4700 40 10 3 ( ( 1000 + 500 + 5500 ) 725000 ) | ¿ 3.25 10 4 ε pt = d c c 0.003 = 642.24 500 500 0.003 = 8.53 10 4 ε pn = ε pe + ε ce + ε pt = 5.13 10 3 + 3.25 10 4 + 8.53 10 4 = 6.31 10 3 f pn = 195000 6.31 10 3 { 0.0332 + 1 0.0332 [ 1 + ( 114 6.31 10 3 ) 12 ] 1 12 } = 1228.57 MPa T p 2 = 1228.57 500 = 614285 N
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Kabel Prestress 3 ε pe = σ pe Ep = Pe Ap Ep = 5500 10 3 4100 195000 = 6.88 10 3 ε ce = | 1 Ec ( Pe Ac
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