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Hello Sir, After this first page, I have highlighted areas in yellow (for question section) where I need explanations and help with certain parts of my question paper. I also have added my calculations as well and I would greatly appreciate it if you could see if I am on the right track with my calculations and if they are correct please. I have not highlighted that section but it is also what I would like to be checked and be able to better understand on what parts I have gone wrong and why so that I can remember and understand concept better. Also for each of the question papers, I need to understand the basis (concept) of why the calculations are done in this way and what is the practical main aim in trying to teach about the subject. Thank you From Elly Experiment 1. – LABORATORY TECHNIQUES Refer to Volumetric glassware and weighing equipment under general information page 93.

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Calculation Questions for Part 1 (KHP) – Experiment 1 Q: Determine the concentration of the NaOH solution. Your report should include all calculations. Show moles of KHP used in each titration and account for reaction stoichiometry. 1. Standardisation of a Sodium Hydroxide Solution The sodium hydroxide solution is standardised using Potassium Hydrogen Phthalate (KHP, C 8 H 5 KO 4 ). The standardisation reaction is as follows: HK(C 8 H 4 O 4 )(aq)+ OH - (aq) → K(C 8 H 4 O 4 ) - (aq) + H 2 O(l) Working out: There were 3 prepared flasks of KHP ( Potassium Hydrogen Phthalate) each with a different mass (up to approx. 0. 6g). Flask name: Mass of KHP added (in grams): Flask 1 0.6229g Flask 2 0.7000g Flask 3 0.6248g Step 1: Working out number of moles of KHP using n=mass/molar mass (n=m/Mr) KHP molar mass: HK(C 8 H 4 O 4 ) = 204.22 g/mol C 8 H 5 KO 4 12.01 (carbon molar mass) x 8 = 96.08 1.008 (hydrogen molar mass) x 5= 5.04 39.10 (potassium molar mass) x 1= 39.10 16.00 (oxygen molar mass) x 4= 64 Total molar mass of KHP = 96.08 + 5.04 + 39.10 + 64 = 204.22g/mol n=mass/molar mass (n=m/Mr) Flask name: Mol of (KHP)=mass/molar mass (n=m/Mr)
Flask 1 0.6229 grams / 204.22 grams/mol = 0.00305 mol Flask 2 0.7000 grams / 204.22 grams/mol = 0.00342 mol Flask 3 0.6248 grams / 204.22 grams/mol = 0.00305 mol

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• Spring '12
• NeerajMisra

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