This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: Prelab: Rotational motion
,1. . _ . . I
Name: 2 l’iCJi'Tf‘if'J 3‘ ill”. .‘_l "U“ 3 Section dayltime W‘O‘PAUV $OQ I‘H‘ri. Consider the apparatus as used in this lab: A cube of mass M = 500 g and side length 30 mm is
free to spin on an axis through the center of one face. A massless pulley on this axis has a ‘ diameter of 2r = 10 mm. An object with m = 50 g is hung from a string wrapped around the
pulley. The assembly is released from rest. Ignore friction. 1. (2 points) What is the time to unwind L = 30 cm of string. Hint: Find the angular acceleration of the apparatus, then ﬁnd the time using A6 = 1 At2 Where A6 = L/r.
Inamanr or ‘Iﬁuﬁa 61': r" 2 %)
T1 ié'mt'h mjzmraw (WW 0‘=.____._————————_('°5)(0\' )( 1
’\ ——’  '03
mfg“: chosofH‘r ‘1‘ (’OS')(5\[03>4 ('5 J
1—. La< 0( .. W3 6‘5 ‘0
r73: Lof mr—i—‘F X: 32l3mJ~/3
T’ [:r’d 0“ "‘6 Q: % 61gb”
MN ”MW mw ﬁrm“ — ,3 +1 29
gma W. r ’ ’7?“ " ‘5?
mgvrmma 0‘ _ m3 5'“?
.. iD/ ~ ’ 1 1 VNA +2 26
m9 <T]—YYW\ mr—I er 8 60 J7:
2. (2 points) What is the kinetic energy of the spinning block after the string unwinds? Use
energy methods.
f: gM(—i) 0‘74 ‘_%.7§.r0'.7 44E ' ZZW
.. ‘ID L ’ " FL » \ \\ I
i 214"" (33%) W" 1 MC: iz(1.87940g)<’Z‘‘Z“""‘“"‘JJ
: [email protected] [0—6Kq mm a: (\Z$\N\‘)S
_ ,L {1
’W 7 1“ L' 2q
 L‘é  2L.
T’ (z 7k“?
Wm: Mgr T— f 103‘)
: F‘ﬂj— 13‘ '6 is
V' :.%‘is
"I .. IQ
5 ~—  9.:
r bd \L €00? “v Ms— 7—:qu
1’; mos: MR 3. (3 points) Use equations 1, 3, and 4 to derive equation 5. W’CJ'O/C \ T? m {Gym} meiom ”Am—Lg VMR, \/,
g0 tomb“ acthag OW FV‘H‘V ('4
{=14 f=rT szrT 4. (3 points) Derive equation 7. WOW? 0*" Ihzj’h'm I‘f EA“:— W634“) a @‘J Ah ...
View
Full Document
 Fall '13
 Mass

Click to edit the document details